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Gennadij [26K]
3 years ago
14

5. Given no other restrictions, what are the domain and range of the following function?

Mathematics
1 answer:
castortr0y [4]3 years ago
3 0

Answer:

Step-by-step explanation:

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What is a CONJUGATE and how do i use it?
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Hey there! Let's figure this question out for you!

A math conjugate, is formed by changing the sign between two terms in a binomial.

An example would be:

4+7x would become 4 - 7x.


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5 0
3 years ago
Whats x^2-2x-2<br><br><br><br><br><br><br><br><br><br><br> akjdcpiwhbfcnkluje
BaLLatris [955]

Answer:

Step-by-step explanation:

1 In general, given a{x}^{2}+bx+cax

​2

​​ +bx+c, the factored form is:

a(x-\frac{-b+\sqrt{{b}^{2}-4ac}}{2a})(x-\frac{-b-\sqrt{{b}^{2}-4ac}}{2a

​2a

​

​−b+√

​b

​2

​​ −4ac

​

​​

​​ )(x−

​2a

​

​−b−√

​b

​2

​​ −4ac

​

​​

​​ )

2 In this case, a=1a=1, b=-2b=−2 and c=-2c=−2.

(x-\frac{2+\sqrt{{(-2)}^{2}-4\times -2}}{2})(x-\frac{2-\sqrt{{(-2)}^{2}-4\times -2}}{2})(x−

​2

​

​2+√

​(−2)

​2

​​ −4×−2

​

​​

​​ )(x−

​2

​

​2−√

​(−2)

​2

​​ −4×−2

​

​​

​​ )

3 Simplify.

(x-\frac{2+2\sqrt{3}}{2})(x-\frac{2-2\sqrt{3}}{2})(x−

​2

​

​2+2√

​3

​

​​

​​ )(x−

​2

​

​2−2√

​3

​

​​

​​ )

4 Factor out the common term 22.

(x-\frac{2(1+\sqrt{3})}{2})(x-\frac{2-2\sqrt{3}}{2})(x−

​2

​

​2(1+√

​3

​

​​ )

​​ )(x−

​2

​

​2−2√

​3

​

​​

​​ )

5 Cancel 22.

(x-(1+\sqrt{3}))(x-\frac{2-2\sqrt{3}}{2})(x−(1+√

​3

​

​​ ))(x−

​2

​

​2−2√

​3

​

​​

​​ )

6 Simplify brackets.

(x-1-\sqrt{3})(x-\frac{2-2\sqrt{3}}{2})(x−1−√

​3

​

​​ )(x−

​2

​

​2−2√

​3

​

​​

​​ )

7 Factor out the common term 22.

(x-1-\sqrt{3})(x-\frac{2(1-\sqrt{3})}{2})(x−1−√

​3

​

​​ )(x−

​2

​

​2(1−√

​3

​

​​ )

​​ )

8 Cancel 22.

(x-1-\sqrt{3})(x-(1-\sqrt{3}))(x−1−√

​3

​

​​ )(x−(1−√

​3

​

​​ ))

9 Simplify brackets.

(x-1-\sqrt{3})(x-1+\sqrt{3})(x−1−√

​3

​

​​ )(x−1+√

​3

​

​​ )

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