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mojhsa [17]
3 years ago
9

What are the constants in this expression?

Mathematics
1 answer:
grandymaker [24]3 years ago
6 0
The constants in this expression are:
B.) -3 and 2/3
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Answer:

p-q= -4

p=q-4

x^2 + px + q=0

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d= b^2-4ac

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= q^2 + 16 -8q - 4q

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given that D=16

q^2 -12q+16 = 16

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=> q^2 = 12q

=> q = 12q/q

=> q= 12

Therefore the value of q is 12 and the value of p is q-4 = 12-4= 8

Hope you understood............

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