Answer:
- The function f(x) = 9,000(0.95)^x represents the situation.
- After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.
- The range values, in the context of the situation, are limited to whole number
Step-by-step explanation:
The "growth" rate is -5%, so the growth factor, the base in the exponential equation, is 1.00-5% =0.95.
Using x=2, we find the population in 2 years is expected to be about ...
f(2) = 9000·0.95^2 ≈ 8123 . . . . about 8120
Using x=4, we find the population in 4 years is expected to be about ...
f(4) = 9000·0.95^4 ≈ 7331 . . . . about 7330
Since population is whole numbers of bees, the range of the function is limited to whole numbers.
The domain of the function is numbers of years. Years can be divided into fractions as small as you want, so the domain is not limited to whole numbers.
The choices listed above are applicable to the situation described.
First get y by its self , then graph , find intersection point and plug in x and y to both equations, see if it makes sense , then the solution must be you intersection point
Answer:the X factor is 7
Step-by-step explanation:
Answer:
The value of y that satisfies the system of equations is 20
Step-by-step explanation:
we have
we know that
The solution of the system of equations is the intersection point both graphs
using a graphing tool
the intersection point is (-3,20)
see the attached figure
therefore
The value of y that satisfies the system of equations is 20
