What is an equation of the line that passes through the points (8,-4) and (6,-5)?
1 answer:
Answer:
y=1/2x-8
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-5-(-4))/(6-8)
m=(-5+4)/-2
m=-1/-2
m=1/2
y-y1=m(x-x1)
y-(-4)=1/2(x-8)
y+4=1/2(x-8)
y=1/2x-8/2-4
y=1/2x-4-4
y=1/2x-8
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