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Alexus [3.1K]
3 years ago
9

How many times will interest be added to the principal in 1 year if the interest is compounded semiannually? A. 1 B. 2 C. 12 D.

6
Mathematics
1 answer:
ValentinkaMS [17]3 years ago
4 0
Semiannual means every six months in a year so the answer is 2
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Factor the expression X2+4X +4
mash [69]

Answer:

A

Step-by-step explanation:

(x+2)(x+2)

= x^2+2x+2x+4

=x^2+4x+4

4 0
3 years ago
4.5/y = 12.5/4 PLEASE HELP!!! SOS
garik1379 [7]

Answer:

y = 1.44

Step-by-step explanation:

What are you aiming to do here?  Please share all instructions with each problem.

If you want to solve 4.5/y = 12.5/4 for y:  Multiply both sides by 4y:

18 = 12.5y.  Then y = 1.44

7 0
3 years ago
What is the solution to the equation 3/<br> x+4+3/2x+8 = 0?
mixas84 [53]

Answer:

X= -4

Step-by-step explanation:

^ you have to isolate the radical than raise each side to the power of its index which gets you

x= -4

5 0
3 years ago
100 points! Please help asap! Look at the picture attached. My teacher said that both 1 and 2 are neither can someone explain wh
Neko [114]

Answer:

Your teacher is right, there is not enough info

Step-by-step explanation:

<h3>Question 1</h3>

We can see that RS is divided by half

The PQ is not indicated as perpendicular to RS or RQ is not indicates same as QS

So P is not on the perpendicular bisector of RS

<h3>Question 2</h3>

We can see that PD⊥DE and PF⊥FE

There is no indication that PD = PF or ∠DEP ≅ FEP

So PE is not the angle bisector of ∠DEF

6 0
3 years ago
Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form
Alex787 [66]

Answer:

y=-\frac{2}{5}x-\frac{1}{5}

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

  • m is the slope
  • b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

m = -\frac{2}{5}

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-\frac{2}{5}x + b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

  • (-3,1). When x of the line is -3, y of the line must be 1.
  • (2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: y=-\frac{2}{5}x + b. b is what we want, the --\frac{2}{5} is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

  • (-3,1). y = mx + b or 1=-\frac{2}{5} * -3 + b, or solving for b: b = 1-(-\frac{2}{5})(-3).b = -\frac{1}{5}.
  • (2,-1). y = mx + b or -1=-\frac{2}{5} * 2 + b, or solving for b: b = 1-(-\frac{2}{5})(2). b = -\frac{1}{5}.

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points  (-3,1) and (2,-1) is y=-\frac{2}{5}x-\frac{1}{5}

8 0
3 years ago
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