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2 years ago

Parallelogram DEFG is graphed on the coordinate plane. It has coordinates D(4, 1), E(10, -3), F(p, -4), and G(-5, q).

Mathematics

1 answer:

labwork [276]2 years ago

5 0

It would be E im pretty sure be you simplify the p and q

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38. Joey paid for 5 hours of batting lessons in March.

Elodia [21]

Answer:

159.75

Step-by-step explanation:

23.50×5=117.5

117.5+42.25=159.75

3 0

2 years ago

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schepotkina [342]

Answer:

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Step-by-step explanation:

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2 years ago

THE BASE AND HEIGHT OF A TRIANGLE WHOSE HEIGHT IS FIVE MORE THAN 6 TIMES ITS BASE

Sedaia [141]

X by 6 then add it all togeth

8 0

2 years ago

Gordon types 3,666 words in 47 minutes. Find the unit rate.

Ad libitum [116K]

Answer:

78 Words per minute

Step-by-step explanation:

A unit rate is simply comparable to an average. Given this, we can say the following:

Unit_Rate = 3666 Words / 47 minutes

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Cheers.

4 0

3 years ago

F(x, y, z) = yzexzi + exzj + xyexzk,

Ghella [55]

$\nabla f(x,y,z)=\mathbf F(x,y,z)\iff\dfrac{\partial f}{\partial x}\,\mathbf i+\dfrac{\partial f}{\partial y}\,\mathbf j+\dfrac{\partial f}{\partial z}\,\mathbf k=yze^{xz}\,\mathbf i+e^{xz}\,\mathbf j+xye^{xz}\,\mathbf k$

$\dfrac{\partial f}{\partial x}=yze^{xz}$
$\implies f(x,y,z)=\dfrac{yz}ze^{xz}+g(y,z)=ye^{xz}+g(y,z)$

$\dfrac{\partial f}{\partial y}=e^{xz}=e^{xz}+\dfrac{\partial g}{\partial y}$
$\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)$

$\dfrac{\partial f}{\partial z}=xye^{xz}=xye^{xz}+\dfrac{\mathrm dh}{\mathrm dz}$
$\implies\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=C$

$f(x,y,z)=ye^{xz}+C$

$\mathbf r(t)=(t^2+5)\,\mathbf i+(t^2-1)\,\mathbf j+(t^2-5)\,\mathbf k$
$\implies\mathbf r(0)=5\,\mathbf i-\mathbf j-5\,\mathbf k$
$\implies\mathbf r(5)=30\,\mathbf i+24\,\mathbf j+20\,\mathbf k$

By the gradient theorem, we have for any path $\mathcal C$ originating at the point (5, -1, -5) and terminating at the point (30, 24, 20),

$\displaystyle\int_{\mathcal C}\mathbf F\cdot\mathrm d\mathbf r=f(\mathbf r(5))-f(\mathbf r(0))=f(30,24,20)-f(5,-1,-5)$
$\implies\displaystyle\int_{\mathcal C}\mathbf F\cdot\mathrm d\mathbf r=24e^{600}+e^{-25}$

4 0

3 years ago