2 years ago

It takes peter 3/5 of an hour to paint one room. How long will it take for him to paint three rooms?

Mathematics

1 answer:

rosijanka [135]2 years ago

6 0

Answer:

1 4/5 hours

Step-by-step explanation:

3/5 x 3 = 9/5 or 1 4/5

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Aleta's puppy gained 3/8 pound each week for 4 weeks. Altogether, how much weight did the puppy gain during the 4 weeks?

kirill [66]

It would be 1 1/2 or 1.5 pounds in total

3/8 as a decimal is .375 (divide 3 by 8)

Then you multiply .375 by 4 then you get 1.5 or 1/ 1/2.

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3 years ago

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PLEASE HELP !

scZoUnD [109]

It will be 33/74
77-41 = 33 and 33/74 is the correct fraction for the cars that are NOT boxcars

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3 years ago

What is 2x + 11y when x = 4 and y = 2? A. 30 B. 38 C. 48 D. 136

Alla [95]

The correct answer is A

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3 years ago

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A+0=0+a=0 is true except for all teal numbers except 0 true or false

jolli1 [7]

Try it with some random number, like a=3.

Is "3+0 = 0+3 = 0" true? No.

If you were doing multiplication, then it would be true, but not with addition.

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3 years ago

T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is

K(x)= $\frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}$

The given curve is y=7 $e^{x}$

${y}''=7e^{x}\\ {y}'=7e^{x}$

k(x)= $\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}$

${k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}$

For Maxima or Minima

${k(x)}'=0$

$7(e^x)(1+49e^{2x})(98e^{2x}-1)=0$

→ $e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0$

$e^{x}=0 , ∧ 1+49e^{2x}=0$ [not possible ∵there exists no value of x satisfying these equation]

→ $98e^{2x}-1=0$

Solving this we get

x= $-\frac{1}{2}\ln{98}$

As you will evaluate ${k(x})}''$ <0 at x= $-\frac{1}{2}\ln98$

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[ $-\frac{1}{2}\ln98$ ,1/√2]

k(x)= $\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}$

k(x)= $\frac{7}{\infty}$

k(x)=0

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3 years ago