Answer:
The answer is B, I just took the test.
Step-by-step explanation:
Answer:
There are a few solutions because there are some fractions and decimals between 8 and 10
Step-by-step explanation:
Let the unknown number be 'x'
If the number is greater than 8 and the same number is less than 10, this can be expressed as;
x>8 and x < 10
Note that if x>8, then 8<x
The resulting inequalities are now;
8<x and x<10
Combining both inequalities we have: 8<x<10
Since the inequality didn't tell us that the variable 'x' is equal to 8 and 10, this means that our solution falls between 8 and 10 and the value of integer that falls within this range is 9. Other values that falls within this range are decimals and fractions.
Therefore it can be concluded that there are a few solutions because there are some fractions and decimals between 8 and 10
Answer:
Step-by-step explanation:
hello : write this expression
X² + y² + 6x – 2y+3 = 0 in the standard form
(x²+6x) +(y²-2y) +3 = 0
(x²+6x+9 -9) +(y²-2y+1 - 1) +3 = 0
(x²+6x+9) -9 +(y²-2y+1) - 1 +3 = 0
(x+3)²+(y-1)² = 7(the standard form)
but : 7 = (√7)²
<h2>the radius is :
√7</h2>
Answer:
wut
Step-by-step explanation:
