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Artist 52 [7]
2 years ago
10

For a certain population of sea turtles, 18 percent are longer than 6. 5 feet. A random sample of 90 sea turtles will be selecte

d. What is the standard deviation of the sampling distribution of the sample proportion of sea turtles longer than 6. 5 feet for samples of size 90 ?.
SAT
1 answer:
Lisa [10]2 years ago
6 0

Based on the information given, it should be noted that the sampling distribution will be 0.0405.

<h3>Sampling distribution.</h3>

From the information given, it was stated that in a certain population of sea turtles, 18 percent are longer than 6. 5 feet and a random sample of 90 sea turtles will be selected.

Therefore, the following can be depicted:

  • p = 0.18
  • n = 90

Therefore, the standard deviation will be calculated thus:

= 0.18 × (1 - p) / 90.

= (0.18 × 0.82) / 90

= 0.00164

Therefore, the square root will be:

= ✓0.00164

= 0.0405.

In conclusion, the correct option is 0.0405.

Learn more about sampling on:

brainly.com/question/17831271

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Answer:

2: 35 and 70

Explanation:

1. The LCM of 5 and 7: <em>35</em>

2. 35 * 2 = 70

3. 35 * 3 = 105, not 2-digit

So, the only 2-digit numbers that are multiples of both 5 and 7 are 35 and 70, so 2.

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Signing up for an IT course where others set the learning goals is an example of what kind of learning?
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i believe the answer would be self directed .

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Based on the given information, determine which company has a lower minimum and find the minimum value. g(x) at (10, 855) f(x) a
Gekata [30.6K]

The minimum production cost of company 2 is greater than the minimum production cost of company 1. We arrived at this value by comparing the production cost of both companies.

<h3>What is meant by minimum production cost?</h3>

The overall cost incurred by a company to manufacture a product or provide services is known as the cost of production.

The objective of every company is to keep this cost at minimum, hence the minimum production cost.

<h3>How do find minimum Production Cost?</h3>

Recall that the production function is given as:

f(x) = 0.25x² - 8x + 600

Inserting the values given by the schedule we have

  1. f(6) = 0.25(6²) - 8(6) + 600 = 561
  2. f(8) = 0.25(8²) - 8(8) + 600 = 552
  3. f(10) = 0.25(10²) - 8(10) + 600 = 545
  4. f(12) = 0.25(12²) - 8(12) + 600 = 540
  5. f(14) = 0.25(14²) - 8(14) + 600 = 537

For company 2, we are given the various production costs as;

x   - g(x)

6  - 862.2

8  - 856.8

10 -  855

12 -  856.8

14 - 862.2

Juxtaposing the above, we can infer that the minimum production cost of company 2 is greater than the minimum production cost of company 1.

Learn more about minimum production cost at:
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#SPJ1

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7 0
2 years ago
Suppose that 3. 33 g of acetone at 25. 0 °c condenses on the surface of a 44. 0-g block of aluminum that is initially at 25 °c.
Vlada [557]

The final temperature on the block is 25 degrees.

Heat is a form of energy. This question shows that energy is transferred from the acetone to the metal block.

Data given;

  • M1 = 3.33g
  • T1 = 25 degrees
  • M2 = 44g
  • T2 = 25 degree
  • C1 = 124.5 J mol K
  • C2 = 0.89 J/g K
<h3>Heat Transfer</h3>

Applying the principles of heat transfer,

Heat loss = Heat gain

m1c1(T1 - T3) = m2c2(T3 - T2)\\3.33*124.5*(25.0 - T3) = 44*0.89*(T3 - 25)\\10364.625 - 414.585T3 = 39.16T3 - 979\\10364.625+979 = 414.585T3 +39.16T3\\11343.25 = 453.745T3\\T3 = \frac{11343.25}{453.745} \\T3 = 24.999\\T3 = 25

From the calculation above, the final temperature on the block is 25 degrees.

Learn more on heat transfer here;

brainly.com/question/15003174

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2 years ago
10 similarities between micro teaching and peer teaching ​
gtnhenbr [62]

Answer:

^^^^^^^^^^^^^^^^^^^

Explanation:

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