What is an angle that is adjacent to AEB

Two particles move in the xy-plane. At time t, the position of particle A is given by x(t)=5t−5 and y(t)=2t−k, and the position

Ipatiy [6.2K]

Answer:

Part A) Not collide

Part B) k = 4

Part C) Particle B is moving fast.

Step-by-step explanation:

Two particles move in the xy-plane. At time, t

Position of particle A:-

$x(t)=5t-5$

$y(t)=2t-k$

Position of particles B:-

$x(t)=4t$

$y(t)=t^2-2t+1$

Part A) For k = -6

Position particle A, (5t-5,2t+6)

Position of particle B, $(4t,t^2-2t-1)$

If both collides then x and y coordinate must be same

Therefore,

For x-coordinate:

5t - 5 = 4t

t = 5

For y-coordinate:

$2t+6=t^2-2t-1$

$t^2-4t-7=0$

$t=-1.3,5.3$

The value of t is not same. So, k = -6 A and B will not collide.

Part B) If both collides then x and y coordinate must be same

For x-coordinate:

5t - 5 = 4t

t = 5

For y-coordinate:

$2t-k=t^2-2t-1$

Put t = 5

$10-k=25-10-1$

$k=4$

Hence, if k = 4 then A and B collide.

Part C)

Speed of particle A, $\dfrac{dA}{dt}$

$\dfrac{dA}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}$

$\dfrac{dA}{dt}=2\cdot \dfrac{1}{5}\approx 0.4$

Speed of particle B, $\dfrac{dB}{dt}$

$\dfrac{dB}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}$

$\dfrac{dB}{dt}=2t-2\cdot \dfrac{1}{4}$

At t = 5

$\dfrac{dB}{dt}=10-2\cdot \dfrac{1}{4}=2$

Hence, Particle B moves faster than particle A

8 0

3 years ago

In a clinical trial, 21 out of 700 patients taking a prescription drug complained of flulike symptoms. Suppose that it is known

svp [43]

Answer:

I don't knowhhhdchdhgdcsjfjdjcfjc

4 0

3 years ago

-5+4(7+k) please help with this equation!

Alex

Answer:

4k+ 23

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The sum of the measures of two angles is 180 degrees. One angle measures 3a and the other angle measures 2a-25 Find a. Then find

e-lub [12.9K]

The sum of the angles equal 180 degrees, so we plug the angle values into an equation:
3a + 2a - 25 = 180.
By combining like terms, this becomes:
5a - 25 = 180
Now, if we add 25 to both sides to isolate a, we get:
5a = 205
Finally, we need to divide both sides by 5 to find a, and we get:
a = 41

Yay! Now we have a. Now we just plug them into the original values! So:
2(41) - 25
Multiply out:
82 - 25
The first angle is equal to 57.

Then we use the second angle:
3(41)
Multiply out:
123
The second angle is equal to 123.

Hope this helps!
~Chrys

8 0

4 years ago

Suppose y varies directly as x. if y=-7 when x=-14, find x when y=10

solniwko [45]

Answer:

20

Step-by-step explanation:

From if y=-7 when x=-14 ----> x=2y

that means when y=10, x=20

4 0

3 years ago

Read 2 more answers