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3 years ago

Please help for both of these questions! its due soon! i'll mark brainlist

Mathematics

1 answer:

Vsevolod [243]3 years ago

7 0

For the first question the answer is
X=-9 or X=10

First you factor the left side of the question
(X+9)(X-10)=0 then u set factors equal to zero
X+9=0 or x -10=0
X=-9 or X=10
Now for question two is the second bubble of answer

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4. You draw a single card from a standard deck of cards. What is the probability

zhenek [66]

OHHHHHHH..........OK

3 0

3 years ago

A bottle contains 2 green gum balls, 2 red gum balls, and 1 blue gum ball.

aliya0001 [1]

Answer:

3/5

Step-by-step explanation:

First add all of the balls together to know the total.

2 + 2 + 1 = 5

Probability of Green: 2/5

Probability of Red: 2/5

Probability of Blue: 1/5

Add red and blue together

2/5 + 1/5 = 3/5

3/5

Brainliest would be appreciated. :)

5 0

3 years ago

Answer ASAP plz I have 2 minutes

earnstyle [38]

250+25= 275 is your answer

5 0

4 years ago

2 Which expression is equivalent to (29) ? 13 g12 qog

sattari [20]

I’m pretty sure that it’s the third answer (q^12)! :)

5 0

3 years ago

n HP laser printer is advertised to print text documents at a speed of 18 ppm (pages per minute). The manufacturer tells you tha

Dominik [7]

Answer:

0.321 is the probability that their mean printing speed of the sample is greater than 17.99 ppm.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 17.39 ppm

Standard Deviation, σ = 4.25 ppm

Sample size = 11

We are given that the distribution of printing speed is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

P(printing speed of the sample is greater than 17.99 ppm.)

P(x > 17.99)

$P( x > 17.99) = P( z > \displaystyle\frac{17.99-17.39}{\frac{4.25}{\sqrt{11}}}) = P(z > 0.468229)\\\\P( z > 0.468229) = 1 - P(z < 0.468229)$

Calculating the value from the standard normal table we have,

$1 - 0.679 = 0321= 32.1\%\\P( x > 17.99) = 32.1\%$

Thus, 0.321 is the probability that their mean printing speed of the sample is greater than 17.99 ppm.

8 0

4 years ago