What two numbers are multiplied to equal 169

Image not writing all that.

elena-14-01-66 [18.8K]

Answer:

imagine

Step-by-step explanation:

8 0

3 years ago

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A school is arranging a field trip to the zoo. The school spends 544.95 dollars on passes for 41 students and 4 teachers. The sc

FrozenT [24]

Answer: I believe it is $20.62

Step-by-step explanation: the student passes+ the food was $845.42 divede that by the 41 students.

7 0

2 years ago

Please help i am super confused on what to do :)

Ludmilka [50]

Answer:

About 9.1 yards tall.

Step-by-step explanation:

So, we can draw the right triangle shown below:

We want to find h.

Since we know the angle and the side adjacent to the angle and we wan to find the opposite side, we will use the tangent ratio:

$\displaystyle \tan(x^\circ)=\frac{\text{Opposite}}{\text{Adjacent}}$

So:

$\displaystyle \tan(20)=\frac{h}{25}$

Therefore:

$\displaystyle h=25\tan(20)$

Use a calculator. Ensure your calculator is in the correct mode (degrees mode):

$h\approx 9.1\text{ yards}$

The goal post is around 9.1 yards tall.

7 0

3 years ago

Based on an indication that mean daily car rental rates may be higher for Boston than for Dallas, a survey of eight car rental c

Elina [12.6K]

Answer:

$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

$df=8+9-2=15$

And the p value would be:

$p_v =P(t_{15}>2.058) =0.0287$

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are signiﬁcantly higher than those in Dallas

Step-by-step explanation:

Data given

$n_1 =8$ represent the sample size for group Boston

$n_2 =9$ represent the sample size for group Dallas

$\bar X_1 =47$ represent the sample mean for the group Boston

$\bar X_2 =44$ represent the sample mean for the group Dallas

$s_1=3$ represent the sample standard deviation for group Boston

$s_2=3$ represent the sample standard deviation for group Dallas

We can assume that we have independent samples from two normal distributions with equal variances and that is:

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

Let the subindex 1 for Boston and 2 for Dallas we want to check the following hypothesis:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t student distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

Replacing we got:

$\S^2_p =\frac{(8-1)(3)^2 +(9 -1)(3)^2}{8 +9 -2}=9$

And the deviation would be just the square root of the variance:

$S_p=3$

The statitsic would be:

$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

$df=8+9-2=15$

And the p value would be:

$p_v =P(t_{15}>2.058) =0.0287$

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are signiﬁcantly higher than those in Dallas

5 0

3 years ago

A school cafeteria sold 1,600 slices of pizza the first week, 800 the second week, 400 the third week if this patter continues,

Mariulka [41]

Answer:

6th week.

Step-by-step explanation:

Each week he is selling 1/2 of the week before so

In the 3rd week he sells 400

- in the 4th week it will be 200

- in 5th week 100

- in 6th seek 50.

7 0

3 years ago

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