How would I go about solving this?

9. The ticket at right has a perimeter of 42 cm.

Liula [17]

Perimeter simply represents the sum of all side lengths of a shape. The length of the missing side of the ticket is 5 cm; the length of gold line on each ticket is 20 cm, and 2 bottles of gold ink are required to draw gold lines on 200 tickets.

I've added the image of the ticket as an attachment.

(a) The missing side length

From the attachment, the 4 unknown side lengths are equal. Represent this side length with L.

So, we have:

$Perimeter =2\times 11 + 4 \times L$

This gives

$2\times11 + 4 \times L = 42$

$22 + 4 \times L = 42$

Collect like terms

$4 \times L = 42-22$

$4 \times L = 20$

Divide both sides by 4

$L =5cm$

(b) The length of the gold lines

There are 4 slant lines and the length of one of the slant lines is 5 cm (as calculated above).

So, the length of the gold line is:

$Gold = 4 \times L$

$Gold = 4 \times 5cm$

$Gold = 20cm$

(c) The number of gold ink bottles.

$n = 200$ --- number of tickets

The length of all gold line in the 200 tickets is:

$Length = 200 \times Gold$

$Length = 200 \times 20cm$

$Length = 4000 cm$

$Length = 4000 \times 0.01m$ ---- convert to meters

$Length = 40m$

Given that:

$Bottle = 20m$ --- 1 bottle for 20 m

The number of bottles (n) is:

$n = \frac{Length}{Bottles}$

$n = \frac{40m}{20m}$

$n = 2$

Hence, 2 bottles of gold ink are enough.

Read more about perimeters at:

brainly.com/question/6465134

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2 years ago

What do you get when you put 1 and 1 together?!!?

chubhunter [2.5K]

Two !!!! ... unless this is some riddle and there's a huge in depth meaningful answer i'm unaware about o.O

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3 years ago

Finding the inverse function for f(x)=1/x^2

Anna [14]

to get the inverse of any expression, we start off by doing a quick switcheroo on the variables and then solve for "y".

$\stackrel{f(x)}{y}=\cfrac{1}{x^2}\implies \stackrel{\textit{quick switcheroo}}{x=\cfrac{1}{y^2}}\implies y^2=\cfrac{1}{x}\implies y=\sqrt{\cfrac{1}{x}}\implies \stackrel{f^{-1}(x)}{y}=\cfrac{1}{\sqrt{x}}$

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3 years ago

What is interest earned on 3500 invested at 6% compounded quarterly or 12 years

enyata [817]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$3500\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &12
\end{cases}
\\\\\\
A=3500\left(1+\frac{0.06}{4}\right)^{4\cdot 12}\implies A=3500(1.015)^{48}$

so, the interest earned then will be A - 3500.

6 0

3 years ago

-5(c-2)=20-5c+10<br> help please

Rudiy27

Answer:

10 is the answer

Step-by-step explanation:

C(5,2) = 5! / 2! (5-2)!

C(5,2) = 5! / 2!3!

C(5,2) = 120/12

C(5,2) = 10

6 0

3 years ago

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