Tickets for a local dog show cost $9.75 each. What is the total cost c, in dollars, for t tickets?
1 answer:
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Answer:
a: We can't determine this from the given information
b: 98%
Step-by-step explanation:
For a:
n = 42
The confidence interval has equal time on each side of µ, so we can add the two end points and divide them by 2 to find the middle of the interaval:
7.4 + 8.6 = 16
16/2 = 8
Now subtract 7.4 from 8 to find the distance from the mean to the end of the interval
8 - 7.4 = 0.6
So the sample mean, plus the calculated error was 0.6 minutes.
We don't have a way of calculating the sample mean with the given information. We could only find the sample standard deviation and the variance.
For b:
We have:
E = 0.6
s = 1.606
n = 42
See attached photo for the calculation of this value
The value is 2.421.
Using a sample size of 42, our degrees of freedom are 41. Use the t-distribution chart to see which level of confidence has 2.421 under it.
The level of confidence is: 98%
We need 41 degrees of freedom, but the chart has only 40, then 45. We can see that 40 has 2.423, and the values go down as the degrees of freedom go up, so 41 will correlate to 2.421
