That would be a right angle
Let ABC be a triangle in the 3rd quadrant, right-angled at B.
So, AB-> Perpendicular BC -> Base AC -> Hypotenuse.
Given: sinθ=-3/5 cosecθ=-5/3
According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
Since sinθ=Perpendicular/Hypotenuse ,
AC=5 and AB=3
Substituting these values in equation (1)
〖BC〗^2=〖AC〗^2-〖AB〗^2
〖BC〗^2=5^2-3^2
〖BC〗^2=25-9
〖BC〗^2=16
BC=4 units
Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
So,cosθ=Base/Hypotenuse Cosθ=-4/5
secθ=Hypotnuse/Base secθ=-5/4
tanθ=Perpendicular/Base tanθ=3/4
cotθ=Base/Perpendicular cotθ=4/3
Because completementary angles add up to 180 degrees (angle 3 and angle 4)
and interior angles of a triangle will also add up to 180 degrees
if you compare these two facts, then angle 4 equals the 2 non adjacent interior angles
Answer:
Step-by-step explanation:
4/6
<em>Question 5</em>
Vertical angles are <u>congruent</u>. Therefore, 
. The sum of two supplementary angles equals 
.
Therefore, 
<em>Question 6</em>
<em>Question 7</em>
<em />
<em>Question 8</em>
<em />
