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Archy [21]
3 years ago
10

Assappp Please Help me

Mathematics
1 answer:
Karolina [17]3 years ago
3 0

Answer:

use photomath!

Step-by-step explanation:

.

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Mr Johnson, the store owner, ordered 48 boxes of jawbreakers. Each box contained 392 pieces of candy. How many lawbreakers did M
n200080 [17]

Answer:

Mr. Johnson would have ordered 18816 jaw breakers.

Step-by-step explanation:

Multiply 392 by 48

5 0
3 years ago
4x4
aivan3 [116]

Answer:

60=2(20)+2x

x=10

Step-by-step explanation:

First, let's write some equations. I wrote 60=2(20)+2x, where x is the length of the room. To solve, first multiply 2 times 20 for 40 (60=40+2x). Then, I subtracted 40 from both sides (20=2x). Finally, I divided on both sides by 2 (10=x).

5 0
4 years ago
What is the error in the work?
N76 [4]

Answer:

you cannot subtract 12x² from -14x they are not "like" terms

Step-by-step explanation:

6 0
4 years ago
A 1,200g block of phosphorus-32, which has a half life of 14.3 days, is stored for 100.1 days. At the end of this period, how mu
Valentin [98]

Answer:

The amount of phosphorus-32 left after 100.1 days is <u>9.3 g</u>.

Step-by-step explanation:

Given:

Initial amount of Phosphorus-32 is, N_0=1200\ g

Time period of decay is, t=100.1\ days

Half life of the block is, t_{1/2}=14.3\ days

Now, final amount left is, N=?

We know that, the decay equation for a radioactive material is given as:

N=N_0e^{-kt}\\k\to decay\ constant

The value of the decay constant is given as:

k=\frac{\ln 2}{t_{1/2}}\\\\k=\frac{0.693}{14.3}=0.0485

Now, plug in all the given values and calculate 'N'. This gives,

N=(1200)e^{(-0.0485\times 100.1)}\\\\N=9.349\approx 9.3\ g

Therefore, the amount of phosphorus-32 left after 100.1 days is 9.3 g

5 0
3 years ago
Plz help me and explain how to do!!!!
kumpel [21]
X is equal to 16. This is because angle Z is congruent to angle X, which means that angle Y and angle W are congruent so if you use the calculation
x + 3 = 2x - 13 you will get that x is 16. 
8 0
3 years ago
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