Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
Answer:
2
Step-by-step explanation:
Answer:
x=-6
Step-by-step explanation:
2x-1 < x+3
5x-1 > 6-2x
x-5 < 0
solve the inequality for x.
x < 4
x > 1
X < 5
find the intersection
X ∑ {1,4}
Alternative form: {x I 1 < x < 4}
∑ indicates summation and is used as a shorthand notation for the sum of terms that follow a pattern. For example, the sum of the first 4 squared integers, 12+22+32+42, follows a simple pattern: each term is of the form i2, and we add up values from i=1 to i=4.
Answer:
158.4 degrees.
Step-by-step explanation:
A line is 180 degress in total so subtract 21.6 from 180. Then you get 158.4
