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2 years ago

5

So now, if you had to describe the location of the point (red dot) of this plane to another person, how would describe it?

1 answer:

GrogVix [38]2 years ago

3 0

To explain the location of the red dot, you simply describe it by its coordinates.

<h3>Coordinates</h3>

The coordinate of a point is the location of the point in a coordinate plane or 2D plane

From the given diagram, the coordinate of the red dot is:

$Red = (4,3)$

This means that, the red dot is located at a coordinate point of (4,3)

Hence, the location of the red dot is simply its coordinates

Read more about coordinates at:

brainly.com/question/4289712

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The width of the Ochoa Community Pool is 20 feet.The length is twice as long as it’s width.What is the perimeter of the pool?

yan [13]

The perimeter is 120
Hope this helps:)

5 0

4 years ago

Jasmine buys the magic carpet on sale for $374. She saved $66 off the regular price. What percent was the price discounted?

Furkat [3]

Answer:

15%

Step-by-step explanation:

Let c represent the regular price of the carpet.

Then:

sale price = regular price less discount

$374 = c - $66

Adding $66 to both sides isolates (solves for) c:

$374 + $66 = c = $440. This is the regular price.

$66

---------- = 0.15 This is the fraction of the regular price by

$440 which the regular price is reduced.

Then the percentage of this discount was 0.15(100%) = 15%

8 0

3 years ago

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

4 years ago

In a rectangle ABCD, A and B are the points (4,2) and (2,8) respectively l. Given that the equation of AC is y=x-2. Find the equ

Nastasia [14]

Hello,

A=(4,2)
B=(2,8)

(AB)≡y-2=(x-4)*(8-2)/(2-4) ==> y=-3x+14
(BC)≡y-8=(x-2)*1/3 ==> y=1/3 x+22/3

4 0

3 years ago

1 1/16 cups of butter times 20 equals how much

iren2701 [21]

13.75 Cups in us cups

8 0

3 years ago

Read 2 more answers