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Alexus [3.1K]
2 years ago
13

PLSSSSS HELLPPPPP!!!!!!

Biology
1 answer:
tigry1 [53]2 years ago
6 0

The skeletal muscle is one of the three types of muscle in the organism. <em>Option a) is correct. From smallest to largest, the parts of a </em><em>skeletal muscle </em><em>are Myofilament, sarcomere, myofibril, muscle fiber, fascicle, muscle. </em>

<h3>The skeletal muscle</h3>

  • It is the most abundant muscle in vertebrates, constituting the somatic musculature.

  • Among its many functions, it proportionates motion to extremities and digits and is responsible for the position and posture of the individual. It also participates in<em> eye movements, respiration, mastication, deglutition, and phonation</em>.

  • The skeletal muscle contracts voluntarily, and its response is fast.

  • Cells composing the striated muscle are significantly longer and multinucleated. They arrange in bundles, where cells are parallel to each other.

<h3>Composition of skeletal muscle</h3>

  • <em>Myofilaments </em>⇒ Actine and miosine

  • <em>Sarcomere</em> ⇒ It is the functional unit with the contractile apparatus. Composed of the Z band, A and I bands, and H zone.

  • <em>Myofibrilles</em> ⇒ They have the Functional units

  • <em>Muscle fibers</em> ⇒ Surrounded by endomysium

  • <em>Fascicle </em>⇒ Group of fibers surrounded by perimysium.

  • <em>Muscle</em> ⇒ Group of fascicles surrounded by epimysium.

Hence, the correct option is a).<em> From smallest to largest, the parts of a </em><em>skeletal muscle </em><em>are Myofilament, sarcomere, myofibril, muscle fiber, fascicle, muscle.</em>

<em />

<em> You can learn more about the</em><em> skeletal muscle</em><em> at</em>

<em>brainly.com/question/1560716</em>

<em>brainly.com/question/1194286</em>

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Answer:

After 6000 years, approximately 500 atoms of carbon-14 will be left in the femur bone of an animal which had 1000 atoms of carbon-14 when the animal died.

Explanation:

The half-life of a radioactive isotope of an element is the time taken for half the atoms present in a given amount of the element to undergo decay or disintegration. For example, the half-life of carbon-14 isotope is 5730 years. This means that, if there are 100 atoms of carbon-14 present in a given sample of a material, in the next 5730 years, approximately, 50 atoms of carbon-14 will be left in the material.

Since the half-life of radioactive isotopes are constant, these radioactive isotopes are used in the determining the ages of ancient life-forms as well as rocks.

In the given example, after 6000 years, approximately 500 atoms of carbon-14 will be left in the femur bone of an animal which had 1000 atoms of carbon-14 when the animal died.

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small group of 100 people decide to isolate themselves from the world and move to a small and remote deserted island. Out of thi
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Answer:

Frequency of p = 0.684

Frequency of p = 0.316

Number of individuals with homozygous dominant (AA) = 47

Number of individuals with heterozygous (Aa)= 43

Number of individuals with homozygous recessive (aa) = 10

Explanation:

Out of 100 people, 10 have albino skin (aa)

So, the frequency of homozygous recessive individuals (q^{2}) is \frac{10}{100} = 0.1

Now, q will be

= \sqrt{q^{2} } = \sqrt{0.1} \\= 0.316

As per Hardy Weinberg's equation -

p + q = 1

Substituting the value of q in above equation, we get -

p + 0.316 = 1p = 1 -0.316\\p = 0.684

Now the frequency of homozygous dominant (AA) will be

p^{2} = 0.684^{2} \\= 0.467

Hence, out of 100 people 0.467 * 100 = 46.7 or 47 people are homozygous dominant (AA)

Like wise out of 100 people 0.1 * 100 = 10 people are homozygous recessive (aa)

As per As per Hardy Weinberg's equation-

p^{2} + q^{2} + 2pq = 1\\

Substituting the values in above equation, we get -

0.467 + 0.316 + 2pq = 1\\2pq = 1 -( 0.467+ 0.1)\\2pq = 0.433

So, out of 100 people 0.433 * 100 = 43.3 or 43 people are heterozygous (Aa)

7 0
3 years ago
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