Eight and two fourths minus three and one third = __

-3x^2+12x-8 in vertex form using the completing the square method! ASAP PLEASE WILL MARK U WHATEVER YOU WANT! WORK NEEDED

atroni [7]

Answer:

-3x2 + 12x - 8

Step-by-step explanation:

Equation at the end of step 1

((0 - 3x2) + 12x) - 8

STEP

2

:

STEP

3

:

Pulling out like terms

3.1 Pull out like factors :

-3x2 + 12x - 8 = -1 • (3x2 - 12x + 8)

Trying to factor by splitting the middle term

3.2 Factoring 3x2 - 12x + 8

The first term is, 3x2 its coefficient is 3 .

The middle term is, -12x its coefficient is -12 .

The last term, "the constant", is +8

Step-1 : Multiply the coefficient of the first term by the constant 3 • 8 = 24

Step-2 : Find two factors of 24 whose sum equals the coefficient of the middle term, which is -12 .

-24 + -1 = -25

-12 + -2 = -14

-8 + -3 = -11

-6 + -4 = -10

-4 + -6 = -10

-3 + -8 = -11

-2 + -12 = -14

-1 + -24 = -25

1 + 24 = 25

2 + 12 = 14

3 + 8 = 11

4 + 6 = 10

6 + 4 = 10

8 + 3 = 11

12 + 2 = 14

24 + 1 = 25

4 0

3 years ago

Read 2 more answers

The beginning balance in the computers account was $2000.the company purchased an additional $1000 worth of computers.the balanc

Amanda [17]

D. Debit of $3000
The balance of account a need to be as much as $3000

7 0

4 years ago

The range of y = - 32x ^ 2 + 90x + 3

mariarad [96]

Given:

The given function is:

$y=-32x^2+90x+3$

To find:

The range of the given function.

Solution:

We have,

$y=-32x^2+90x+3$

It is a quadratic function because the highest power of the variable x is 2.

Here, the leading coefficient is -32 which is negative. So, the graph of the given function is a downward parabola.

If a quadratic function is $f(x)=ax^2+bx+c$ , then the vertex of the quadratic function is:

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

In the given function, $a=-32,b=90,c=3$ .

$\dfrac{-b}{2a}=\dfrac{-90}{2(-32)}$

$\dfrac{-b}{2a}=\dfrac{-90}{-64}$

$\dfrac{-b}{2a}=\dfrac{45}{32}$

The value of the given function at $x=\dfrac{45}{32}$ is:

$y=-32(\dfrac{45}{32})^2+90(\dfrac{45}{32})+3$

$y=\dfrac{2121}{32}$

The vertex of the given downward parabola is $\left(\dfrac{45}{32},\dfrac{2121}{32}\right)$ . It means the maximum value of the function is $y=\dfrac{2121}{32}$ . So,

$Range=\left\{y|y\leq \dfrac{2121}{32}\right\}$

$Range=\left(-\infty, \dfrac{2121}{32}\right ]$

Therefore, the range of the given function is $\left (-\infty, \dfrac{2121}{32}\right ]$ .

8 0

3 years ago

The percent change from 45 to 90 is

NeTakaya

A change from 45 to 90 represents a positive change (increase) of 100%

Use the formula found below on this webpage to find the percent change by replacing the given values:

Percent change = New - Old|Old| × 100%

Percent change = 90 - 45|45| × 100% =

4545 × 100 = 100% (increase)

Where: 45 is the old value and 90 is the new value. In this case we have a positive change (increase) of 100 percent because the new value is greater than the old value.

6 0

3 years ago

Fund the error in the solution and then solve correctly

Maurinko [17]

Answer:

yolo it

Step-by-step explanation:

3 0

4 years ago

Eight and two fourths minus three and one third = ___