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2 years ago

Please help thank you!

Mathematics

1 answer:

Arte-miy333 [17]2 years ago

7 0

Answer:

golf: $10
batting: $2.50

Step-by-step explanation:

We can write two equations in the two unknowns using the given relations. Let g and b represent the costs of a round of golf and a turn in the batting cage, respectively.

5g +4b = 60 . . . . . Sylvester's expense

3g +6b = 45 . . . . . Lin's expense

Dividing the second equation by 3 gives ...

g +2b = 15 ⇒ 2b = 15 -g

Substituting into the first equation, we have ...

5g +2(2b) = 60

5g +2(15 -g) = 60 . . . . . substitute for 2b

3g = 30 . . . . . . . . . subtract 30, collect terms

g = 10 . . . . . . . divide by 3

2b = 15 -10 = 5 . . . . use the value of g to find b

b = 2.5 . . . . . . . . divide by 2

Mini golf costs $10 per round; batting cages cost $2.50 per turn.

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Answer please !!!!!!!

Afina-wow [57]

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2 years ago

It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i

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Answer:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 55, \pi = \frac{24}{55} = 0.4364$

93% confidence level

So $\alpha = 0.07$ , z is the value of Z that has a pvalue of $1 - \frac{0.07}{2} = 0.965$ , so $Z = 1.81$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 - 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.3154$

The upper limit of this interval is:

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3 years ago

WILL GIVE BEST RESPONSE

tino4ka555 [31]

We will use demonstration of recurrences1) for n=1, 10= 5*1(1+1)=5*2=10, it is just
2) assume that the equation 10 + 30 + 60 + ... + 10n = 5n(n + 1) is true, for all positive integers n>=1
3) let's show that the equation is also true for n+1, n>=1
10 + 30 + 60 + ... + 10(n+1) = 5(n+1)(n + 2)
let be N=n+1, N is integer because of n+1, so we have
10 + 30 + 60 + ... + 10N = 5N(N+1), it is true according 2)
so the equation is also true for n+1,
finally, 10 + 30 + 60 + ... + 10n = 5n(n + 1) is always true for all positive integers n.

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3 years ago

In a survey of 702 students, 2/3 liked rock music. How many students liked rock music?

MissTica

Answer:

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3 years ago

Which of the following is the correct ratio for converting kilograms to grams

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Answer:

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Step-by-step explanation:

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3 years ago