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klemol [59]
2 years ago
10

Special right triangles

Mathematics
1 answer:
Tasya [4]2 years ago
8 0
Right angle is the answer I think ( not sure though )
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I need help <br> Solve for a<br> a+b=c
antiseptic1488 [7]

Step-by-step explanation:

What is it that you need help with exactly?

A+B=C

It's already been solved. Do you need it in a different form?

(a/(b/c)

7 0
3 years ago
What are the approximate solutions of 2x^2 + x = 14, rounded to the nearest hundredth?
Slav-nsk [51]
Hello,

2x²+x-14=0
Δ=1+4*14*2=113

x=(-1-√113)/4=-2,8839...≈-2.88
or x=(-1+√113)/4=2,40753≈2.41


7 0
3 years ago
A conical paper cup has a radius of 2 inches. Approximate, to the nearest degree, the angle β (see the figure) so that the cone
Aneli [31]
I don't know where the angle β is, so I will make the assumption that tanβ = h/r
V = \frac{1}{3} \pi r^{2} h

V volume = 60
r radius = 2
h = r tanβ

tan \beta = \frac{3V }{ \pi  r^{3} } = \frac{ 180}{25,1} = 7,17 \\  \\  \beta = 82
7 0
3 years ago
Find the altitude of an equilateral triangle whose perimeter is 18
Rainbow [258]

Answer:

3√3 units

Step-by-step explanation:

We are asked to find the altitude of the equilateral triangle whose perimeter is 18 . Firstly let us find the side of the∆.

\rm \implies a + a + a = 18 \\\\\rm\implies 3a = 18  \\\\\rm\implies a = 6

Now we know that in a equilateral triangle , the altitude of the triangle with side length a is ,

\rm\implies Altitude =\dfrac{\sqrt3}{2} a

Plug in the value of a that is 6 , we will get ,

\rm\implies Altitude =\dfrac{\sqrt 3}{2} a  \\\\\rm\implies Altitude =\dfrac{ \sqrt3}{2}\times 6  \\\\\rm\implies Altitude = \sqrt3 \times 3  \\\\\rm\implies\boxed{ \bf Altitude = 3\sqrt3 \ units }

5 0
3 years ago
10 men and 5 women are meeting in a conference room. Four people are chosen at random from the 15 to form a committee. (a) What
nata0808 [166]

Answer:

Step-by-step explanation:

Given

There are 10 men and 5 women in a conference room

total People=15

(a)Probability that the committee consists of 2 men and 2 women

we have to select from 10 men and 5 women

P=\frac{^5C_2\times ^{10}C_2}{^{15}C_4}

(b)Bob and Jane end up on the same committee

as bob and Jane are necessary to include so there are 4 women and 9 men left to select remaining 2 person

P=\frac{^{13}C_2}{^{15}C_4}

(c)Bob is in the committee but Jane is not

9 men and 4 women left to choose other 3 person

P=\frac{^{13}C_3}{^{15C_4}}

7 0
3 years ago
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