Do a gallon man 1G 4Q 2P 2C
Step-by-step explanation:
1. y=(x-2)²-9
Using Formula (a-b)²=a²-2ab=b²
y=(x²-4x+4)-9
y=x²-4x-5
Using Mid term Break
y=x²-5x+x-5
y=x(x-5)+1 (x-5)
y=(x+1)(x-5)
2. y= -(x-5)²+16
Using the same formula as above
y= -(x²-10x+25)+16
y= -x²+10x-25+16
y= -x²+10x -9
Taking (-) as Common
y= -(x²-10x+9)
y= -(x²-9x-x+9)
y= -[x(x-9)-1(x-9)]
y= -(x-1)(x-9)
Using the defects method, which relationship represents the Law of Cosines if the measure of the included angle between the sides a and b of ΔABC is less <span>than 90°?
</span><span>C) area of square c2 = area of square a2 + area of square b2 − area of defect1 − area of defect2
</span>
I'm really not familiar with this subject area but I have encountered this problem before and this answer was confirmed.
Answer:
b. x=11/c
Step-by-step explanation:
cx - 4 = 7
cx = 11
x = 11/c
