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2 years ago

12

Mike made four of his truck payments late and was fined four late fees. If each late fee was $10, how much did he pay in late fe

es?

1 answer:

labwork [276]2 years ago

6 0

Answer:

$40, how I got this is I took $10 * 4 late fees and there is your $40

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2 years ago

Polygon F has an area of 36 square units. Aimar drew a scaled version of Polygon F and labeled it Polygon G. Polygon G has an ar

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3 years ago

A biker travels 55 miles in 5 hours. What is the bikers speed in miles per hour? *

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3 years ago

If the level of significance of a hypothesis test is raised from 0.005 to 0.2, the probability of a type ii error will:_________

LiRa [457]

The probability of type II error will decrease if the level of significance of a hypothesis test is raised from 0.005 to 0.2.

<h3 /><h3>What is a type II error?</h3>

A type II error occurs when a false null hypothesis is not rejected or a true alternative hypothesis is mistakenly rejected.

It is denoted by 'β'. The power of the hypothesis is given by '1 - β'.

<h3>How the type II error is related to the significance level?</h3>

The relation between type II error and the significance level(α):

The higher values of significance level make it easier to reject the null hypothesis. So, the probability of type II error decreases.
The lower values of significance level make it fail to reject a false null hypothesis. So, the probability of type II error increases.
Thus, if the significance level increases, the type II error decreases and vice-versa.

From this, it is known that when the significance level of the given hypothesis test is raised from 0.005 to 0.2, the probability of type II error will decrease.

Learn more about type II error of a hypothesis test here:

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1 year ago

Please help! The volume of an inflated spherical water balloon is 121,500 pi millimeters to the third. What is the radius of the

irga5000 [103]

Answer:

The radius of the inflated spherical balloon is 45 millimeters.

Step-by-step explanation:

Volume of the spherical water balloon = 121,500 pi cubic millimeters

Let the radius of the balloon = r

Now, Volume of a Sphere = $\frac{4}{3} \pi r^{3}$

⇒ $\frac{4}{3} \pi r^{3} = 121,500 \pi$

On solving for the value of r, we get:

$r^{3} = \frac{121,500\times 3}{4} = 91125\\ \implies r = \sqrt[3]{91125}$

or, r = 45 millimeter

Hence, the radius of the inflated spherical balloon is 45 millimeters.

5 0

3 years ago