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Anna [14]
2 years ago
15

Ribosomes can be found attached to the endoplasmic reticulum true or false.

SAT
1 answer:
Katena32 [7]2 years ago
4 0

Answer:

i believe that the correct answer is true

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A 100-n weight is hung at the middle of a 4-m long horizontal clothesline. If the middle of the clothesline sags by 1 m, what is
Elena L [17]

The tension on each segment of the clothesline is :  110 N

<u>Given data : </u>

mass of object = 100 n  = 10 kg

Horizontal distance of clothesline = 4 m

middle of clothesline sag s by : 1m

<h3 /><h3>Determine the tension on each segment of clothesline</h3>

<u>First step</u> : calculate the horizontal angle made by the sagging

β = arctan ( 1 m / 2m )  ----- ( 1 )

  = arctan ( 0.5 )

  ≈ 26.57°

Note : Tension in th y axis ( Ty ) = Tsinβ

Therefore :

Tension on each segment can be calculated using the formula below

2Tsinβ - mg = 0

solve for T

T = mg / 2sinβ

  = ( 10 * 9.8 ) / 2 * sin 26.57°

  = 98 / 0.89

  = 110 N

Hence we can conclude that the tension on each segment of the clothesline is : 110 N

Learn more about Tension calculations : brainly.com/question/24994188

7 0
2 years ago
A sample of aluminum metal absorbs 9. 86 j of heat, upon which the temperature of the sample increases from 23. 2°c to 30. 5°c.
Alenkinab [10]

Answer:

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Explanation:

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Jackie says that 200 ÷ 18 is he corrct
Dmitriy789 [7]

Answer:

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Explanation:

3 0
3 years ago
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3 years ago
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A sample of oxygen gas is confined at 127°c and 0.80 atm. if volume of the container holding the gas stayed the same, what would
sveticcg [70]

Based on the calculations, the pressure of this gas sample at 27°C is equal to 0.17 atm.

<h3>How to determine the final pressure.</h3>

In order to calculate the final pressure of an ideal gas at constant volume, we would apply Gay Lussac's law.

Mathematically, Gay Lussac's law is given by this formula;

P\;\alpha \;T\\\\P=kT

<u>Where:</u>

  • P is the pressure.
  • T is the temperature.
  • k is the constant of proportionality.

Substituting the given parameters into the formula, we have;

\frac{P_1}{T_1} =\frac{P_2}{T_2} \\\\\frac{0.80}{127} =\frac{P_2}{27} \\\\0.0063 =\frac{P_2}{27}\\\\P_2 = 0.0063 \times 27

Final pressure = 0.17 atm.

Read more on temperature here: brainly.com/question/888898

3 0
2 years ago
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