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Anna [14]
3 years ago
15

Ribosomes can be found attached to the endoplasmic reticulum true or false.

SAT
1 answer:
Katena32 [7]3 years ago
4 0

Answer:

i believe that the correct answer is true

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Strike-slip faults indicate rocks are sliding past each other horizontally, with little to no vertical movement. ...

Normal faults create space. ...

Reverse faults, also called thrust faults, slide one block of crust on top of another.

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1. A group of 1,000 randomly chosen individuals took a test that measures verbal reasoning and also a test that measures problem
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Satya, nina, and iana each have a 3/4 chance of going to café georgia for an afternoon coffee at 1:00pm. Bohan will only go to c
larisa86 [58]

Using the binomial distribution, it is found that there is a 0.9844 = 98.44% probability that bohan goes to café georgia for a coffee today.

For each friend, there are only two possible outcomes, either they go to the cafe, or they do not. The probability of a friend going to the cafe is independent of any other friend, hence, the binomial distribution is used to solve this question.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • There are 3 friends, hence n = 3.
  • They all go to the cafe with a 3/4 probability, hence p = 3/4 = 0.75.

The probability at least one goes is:

P(X \geq 1) = 1 - P(X = 0)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.75)^{0}.(0.25)^{3} = 0.0156

Then:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0156 = 0.9844

0.9844 = 98.44% probability that bohan goes to café georgia for a coffee today.

You can learn more about the binomial distribution at brainly.com/question/24863377

3 0
3 years ago
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