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2 years ago

Gina is painting the rectangular tool chest shown in the diagram

Mathematics

1 answer:

Nikitich [7]2 years ago

6 0

Answer:

2,880

Step-by-step explanation:

24X12X10=2,880

Hopes This Helps :)

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Write a variable expression to describe the rule for the sequence. Then find the 100th term. 35, 36, 37,...

Dmitry [639]

Given expression is 35, 36, 37, 38...

First term a = 35

Common difference d = 36-35 = 1

Nth term of arithmetic sequence is:

$n_{th} = a+ (n-1)d$

$n_{th}= 35+(n-1)(1)$

$n_{th} = 34+n$

To find the 100th term, substitute n = 100

$n_{100} = 34 +100$

$n_{100} =134$

Correct option is B

5 0

2 years ago

Describe and correct the error in finding the slope of the line passing through (0,0) and (4,5)

Verdich [7]

Answer:

Step-by-step explanation:

o,o is in the origin

6 0

3 years ago

Evaluate −2(2/5)^10x for x=1/5.

kenny6666 [7]

Answer:

-8/25

Step-by-step explanation:

I took the test and i got it right

8 0

2 years ago

Jackson used the process of completing the square to solve the equation 2x2−12x=−6.

Nikolay [14]

Answer:

$x=3-\sqrt{6},x=3+\sqrt{6}$

Step-by-step explanation:

we are given equation as

$2x^2-12x=-6$

Since, we have to solve it by using complete square

so, firstly we will complete square

and then we can solve for x

step-1:

Factor 2 from both sides

$2(x^2-6x)=-3\times 2$

step-2:

Simplify it

$x^2-6x=-3$

step-3:

Add both sides 3^2

$x^2-6x+3^2=-3+3^2$

now, we can complete square

$(x-3)^2=6$

step-4:

Take sqrt both sides

$(x-3)=-\sqrt{6},(x-3)=\sqrt{6}$

step-5:

Add both sides by 3

we get

$x=3-\sqrt{6},x=3+\sqrt{6}$

3 0

3 years ago

Water pours into a tank at the rate of 2000 cm3/min. The tank is cylindrical with radius 2 meters. How fast is the height of wat

Gennadij [26K]

Volume of water in the tank:

$V=\pi (2\,\mathrm m)^2h=\pi(200\,\mathrm{cm})^2h$

Differentiate both sides with respect to time t :

$\dfrac{\mathrm dV}{\mathrm dt}=\pi(200\,\mathrm{cm})^2\dfrac{\mathrm dh}{\mathrm dt}$

V changes at a rate of 2000 cc/min (cubic cm per minute); use this to solve for dh/dt :

$2000\dfrac{\mathrm{cm}^3}{\rm min}=\pi(40,000\,\mathrm{cm}^2)\dfrac{\mathrm dh}{\mathrm dt}$

$\dfrac{\mathrm dh}{\mathrm dt}=\dfrac{2000}{40,000\pi}\dfrac{\rm cm}{\rm min}=\dfrac1{20\pi}\dfrac{\rm cm}{\rm min}$

(The question asks how the height changes at the exact moment the height is 50 cm, but this info is a red herring because the rate of change is constant.)

7 0

3 years ago