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3 years ago

Gina is painting the rectangular tool chest shown in the diagram

Mathematics

1 answer:

Nikitich [7]3 years ago

6 0

Answer:

2,880

Step-by-step explanation:

24X12X10=2,880

<em>Hopes This Helps :)</em>

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Answer: 336 sq ft

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3 years ago

Your investment of $18,100 at 13.6% compounded annually for 7.5 years will be worth how much?

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Jill’s front door is 42” wide and 84” tall. She purchased a circular table that is 96 inches in diameter. Will the table fit thr

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Yes she will fit it because 42+84=126. 126 is more than 96.

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3 years ago

Which of the sets of ordered pairs represents a function?

IgorC [24]

Answer:

Neither set A nor set B represents a function.

Step-by-step explanation:

According to the definition of a function, for each input there exists a unique output. In other word for each value of x there exists unique value of y.

In set A we have four ordered pair (-4,5),(1,-1),(2,-2) and (2,3).

It means for x=2, we have two values of y, i.e., -2 and 3.

Since for a single value of x there exist more than one value of y, therefore set A is not a function.

In set B we have four ordered pair (2,2),(3,-2),(9,3) and (9,-3).

It means for x=9, we have two values of y, i.e., -3 and 3.

Since for a single value of x there exist more than one value of y, therefore set B is not a function.

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3 years ago

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What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu

inn [45]

Answer:

$\frac{(x+5)(x+2)}{x(x-3)(x+3)}$

Step-by-step explanation:

The given expression is

$\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}$

First, we need to factor each denominator

$\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}$

So, the least common factor (LCF) is $x(x-3)(x+3)$ , because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

$\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}$

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

$\frac{(x+5)(x+2)}{x(x-3)(x+3)}$

Therefore, the expression is equivalent to

$\frac{(x+5)(x+2)}{x(x-3)(x+3)}$

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3 years ago

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