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iren [92.7K]
2 years ago
11

A. How can you represent the total number of eggs in the shipment using diagrams or images? Explain

Mathematics
1 answer:
STatiana [176]2 years ago
3 0

Answer:

start with the initial amount of eggs you have and slowly start to reduce the count as the eggs start to diminish.

Step-by-step explanation:

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PLEASE HELP ASAP!!
Gala2k [10]

Answer:

7.2 feet

Step-by-step explanation:

plug in x = 3 since we are looking for the height after the 3rd bounce

4(0.6)(3)

4(1.8)

7.2

4 0
2 years ago
Bob’s Burger Place made 11 burgers with onions and 7 burgers without onions. What is the ratio of the number of burgers without
Anika [276]

Answer:

7:11

Step-by-step explanation:

There is no way to simplify the ratio.

7 0
2 years ago
Read 2 more answers
How do you find the product of -2(3.1)
Alexxandr [17]

Answer:

- 6.2

Step-by-step explanation:

The product of - 2 (3.1) is - 6.2.

Brackets mean to multiply so we have to multiply the - 2 by 3.1 which gives a result of - 6.2.

5 0
3 years ago
determine whether the given ordered pair is a solution to the system of equations. 6x-2y=24 -3x+3y=24 and (10,18) yes, it is a s
Anika [276]

Answer:

I love algebra anyways  

the ans is in the picture with the steps  

(hope it helps can i plz have brainlist :D hehe)

Step-by-step explanation:

7 0
3 years ago
in a five character password the first two characters must be digits and the last three characters must be letters if no charact
Vilka [71]

Answer:

1,404,000 unique passwords are possible.

Step-by-step explanation:

The order in which the letters and the digits are is important(AB is a different password than BA), which means that the permutations formula is used to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

In this question:

2 digits from a set of 10(there are 10 possible digits, 0-9).

3 characters from a set of 26. So

P_{10,2}P_{26,3} = \frac{10!}{8!} \times \frac{26!}{23!} = 10*9*26*25*24 = 1404000

1,404,000 unique passwords are possible.

5 0
3 years ago
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