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Aleksandr [31]
2 years ago
8

In 1980 (before the era of in-vitro fertilization), there were 3,612,258 births in the United States (according to the U.S. Cens

us Bureau), of which 68,339 births were to twins and 1,337 births were to triplets or more.1. What was the probability of having multiples (twins or more) in 1980?
Mathematics
1 answer:
scoray [572]2 years ago
8 0

Answer:

There was a 1.93% probability of having multiples (twins or more) in 1980.

Step-by-step explanation:

There were 3,612,258 births in the US in 1980.

Of those,

68339 + 1337 = 69676 were multiplies.

So

What was the probability of having multiples (twins or more) in 1980?

P = \frac{69676}{3612258} = 0.0193

There was a 1.93% probability of having multiples (twins or more) in 1980.

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