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Aleksandr [31]
2 years ago
8

In 1980 (before the era of in-vitro fertilization), there were 3,612,258 births in the United States (according to the U.S. Cens

us Bureau), of which 68,339 births were to twins and 1,337 births were to triplets or more.1. What was the probability of having multiples (twins or more) in 1980?
Mathematics
1 answer:
scoray [572]2 years ago
8 0

Answer:

There was a 1.93% probability of having multiples (twins or more) in 1980.

Step-by-step explanation:

There were 3,612,258 births in the US in 1980.

Of those,

68339 + 1337 = 69676 were multiplies.

So

What was the probability of having multiples (twins or more) in 1980?

P = \frac{69676}{3612258} = 0.0193

There was a 1.93% probability of having multiples (twins or more) in 1980.

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olganol [36]
The formula of the surface area of the rectangular prism is equal:
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3 years ago
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Helen [10]

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30.06 degree Celsius at 4:00 PM.

Step-by-step explanation:

We have been given that on a hot Saturday morning while people are working​ inside, the air conditioner keeps the temperature inside the building at 24 degrees C. At noon the air conditioner is turned​ off, and the people go home. The temperature outside is a constant 35 degrees C for the rest of the afternoon. The time constant for the building is 5 ​hr. We are asked to find the temperature inside the building at 4:00 PM.

We will use Newton's law of cooling to solve our given problem.

T(t)=M_0+(T_0-M_0)e^{-kt}, where

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Upon substituting our given values in Newton's cooling law, we will get:

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