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vovikov84 [41]
3 years ago
12

In his boat, Sheldon can travel 45 mi downstream in the same time that it takes to travel 9 mi upstream. If the rate of the curr

ent is 6 mph, find the rate of the boat in
still water.
Mathematics
1 answer:
Nataliya [291]3 years ago
7 0

Answer:

9 mph

Step-by-step explanation:

-let x be the speed of current and t be time. The speed equation for both directions can then be represented as:

Speed=\frac{Distance}{Time}\\\\\#Upstream\\(u-6)t=9\\\\\#Donwstream\\\\(u+6)t=45

#Since t is equal in both, we can do away with t.

#We the divide the downstream equation by the upstream equation as:

\frac{u+6}{u-6}=\frac{45}{9}\\\\(u+6)=5(u-6)\\\\u+6=5u-30\\\\4u=36\\\\u=9

Hence, the boat's speed in still water is  9 mph

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Find the x- and y-intercepts for the graph of the equation: 9x-6y=3
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<span>9x-6y=3
</span>x -intercepts y = 0, 9x = 3 then x = 1/3
y -intercepts x = 0, -6y = 3 then y = -1/2

answer
x -intercepts (1/3, 0)
y -intercepts (0, -1/2)
5 0
3 years ago
Suppose a computer manufacturer has the total cost function
S_A_V [24]

Answer:

(a)  P(x) = 300 x - 3600

(b)  P(340) = $ 98400

(c)  At least 12 items must be sold to avoid losing money.

Step-by-step explanation:

Part (a):

The Profit function is the difference between the revenue function (R(x)) and the Cost (C(x)) function:

P(x) = R(x) - C(x)

P(x) = 384 x - [84 x + 3600]

P(x) = 384 x - 84 x - 3600

P(x) = 300 x - 3600

Part (b):

The profit on 340 items is:

P(340) = 300 (340) - 3600

P(340) = 102000 - 3600

P(340) = $ 98400

Part (c):

To avoid losing money, the profit P(x) has to be larger or equal than zero. That is:

P(x) \geq 0

300 x -3600  \geq 0

300 x  \geq 3600

x  \geq 3600/300

x  \geq 12

So at least 12 items must be sold to avoid losing money.

7 0
2 years ago
population growth problem: the deer population in georgia was 450,000 in 2010, and the population doubles every 5 years. in what
VikaD [51]
We know that in 2020 the population of deer will be 900,000 based on the given numbers. In another 5 years the population will be over 1 million (1,350,000) in order to calculate when it will reach 1 million we need to see how much growth is gained per year. I believe to obtain that information we will need to divide 450,000 by 5 that equals 90,000 a year. So if I’m 2020 the population of deer will be 900,000 than add 90,000 until you reach your 1 million marker. In this case 2021 would be 990,000 thousand so 2022 would be 1,080,000. So your answer should be year 2022. Hope that helps.
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2 years ago
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BartSMP [9]
D............a raisin is about 1 cm long

6 0
3 years ago
Read 2 more answers
The average cost when producing x items is found by dividing the cost function, C(x), by the number of items, x. When is the ave
kakasveta [241]

Answer:

<em>The average cost is less than 100 when the number of items x is greater than 2</em>

Step-by-step explanation:

The cost equation is C(x) = 10x + 180

The average cost Cp = \frac{C(x)}{x}

We want to know when the cost Cp is less than 100.

So

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For x> 0

\frac{180}{90}

x> 2

The average cost is less than 100 when x>2

8 0
3 years ago
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