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klio [65]
2 years ago
8

Help wit this please

Mathematics
1 answer:
kotegsom [21]2 years ago
5 0

Answer:

1: Out: 5, 8, 11, 14

2: Out: 2, 7, 10, 11

3: Out: 11  Rule: Add 4

4: Out: 6  Rule: Add 4

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Lana works as an accountant and ears $78,832 per year. What is Lana’s approximate weekly earnings
Nadusha1986 [10]

Answer:

<u>$1516</u>

Step-by-step explanation:

$78,832 / 52 weeks = $1516 per week

-If Lana worked every week of the year with no vacation with only weekends as a break.

7 0
3 years ago
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Find the volume of the following<br> square pyramid.<br> 6 cm<br> 4 cm<br> 4 cm<br> V = [?] cm3
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((6 cm) (4 cm) (4cm) ) 3

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In the similar triangles below, what is the measure of ∠B<br><br> 37°<br> 53°<br> 74°<br> 90°
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How many solutions does this equation have 3x + 5 = 2x + 5 + x
ki77a [65]

Answer:

True for all x

Step-by-step explanation:

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8 0
3 years ago
If there are 180 grams of radioactive material with a half-life (decrease by half or 50%) of 1 hour, how much of the radioactive
Alexeev081 [22]

Answer:

After 3 hours there is left 22.5 grams of radioactive material.

Step-by-step explanation:

We can calculate the mass of radioactive material remaining after 3 hours, by using the decay equation:           

N_{t} = N_{0}*e^{-\lambda t}     (1)

Where:

N_{0}: is the initial mass = 180 g

N_{t}: is the remaining mass after time t

λ: is the decay constant

The decay constant is given by:

\lambda = \frac{ln(2)}{t_{1/2}}

Where t_{1/2} = 1 h.

By entering λ into equation (1) we hve:

N_{t} = N_{0}*e^{-\frac{ln(2)}{t_{1/2}} t}

N_{t} = 180 g*e^{-\frac{ln(2)}{1 h} 3 h} = 22.5 g

Therefore, after 3 hours there is left 22.5 grams of radioactive material.

I hope it helps you!          

3 0
3 years ago
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