What is 2and7/16 + 3/4

What is the domain and range of f(x)=log(x+6)-4

jarptica [38.1K]

Log of 0 or <0 does not exist

so x + 6 must be > 0

so the domain is (-6, +infinity)

or x > -6

4 0

3 years ago

if the cost of a dress is multiplied by 5/8 the price then becomes $30.00 what was the original price

Alik [6]

Let's label the original price of the dress as x. We know that
$x \times \frac{5}{8} = 30$
so that means that we can find x by dividing both sides by 5/8:
$x = 30 \div \frac{5}{8}$
A simple rule for dividing fractions is 'Keep Change Flip'. You keep the first number/fraction the same, you change the ÷ to a × and you flip the second fraction. Through this rule, we can now solve the equation much more easily:
$x = 30 \times \frac{8}{5} \\ x = \frac{240}{5} \\ x = 48$
Therefore, the original price of the dress was $48

6 0

3 years ago

What does 3(7y − 1) =

Bess [88]

Answer: 21y-3

Step-by-step explanation:

3(7y-1)=

3(7y)-3(1)=

21y-3

5 0

3 years ago

Read 2 more answers

The magic dragon cigarette company claims that their cigarettes contain an average of only 10 mg of tar. a random sample of 100

9966 [12]

Answer:

$t=\frac{11.5-10}{\frac{4.5}{\sqrt{100}}}=3.333$

Critical value

The significance is 5% so then $\alpha=0.05$ and $\alpha/2=0.025$ then the critical value for this case would be $z_{\alpha/2}= 1.64$ . Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis and we can conclude that the true mean is higher than 10 mg

P value

The p value would be given

$p_v =P(z>3.333)=0.000434$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 10 mg

Step-by-step explanation:

Information given

$\bar X=11.5$ represent the sample mean

$\sigma=4.5$ represent the population standard deviation

$n=100$ sample size

$\mu_o =10$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is higher than 10mg, the system of hypothesis would be:

Null hypothesis: $\mu \leq 10$

Alternative hypothesis: $\mu > 10$

the statistic for this case would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing we got:

$t=\frac{11.5-10}{\frac{4.5}{\sqrt{100}}}=3.333$

Critical value

The significance is 5% so then $\alpha=0.05$ and $\alpha/2=0.025$ then the critical value for this case would be $z_{\alpha/2}= 1.64$ . Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis and we can conclude that the true mean is higher than 10 mg

P value

The p value would be given

$p_v =P(z>3.333)=0.000434$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 10 mg

6 0

3 years ago

Please help me as soon as possible!

S_A_V [24]

Answer:

9.53 AU

Step-by-step explanation:

4 0

2 years ago