<h2>
Answer:</h2>
The graph is shown in the Figure below
<h2>
Step-by-step explanation:</h2>
In this exercise, we have an equation. On the left side we have a straight line with slope 
and there is no any y-intercept. On the right side, on the other had, we also have a straight line, but the slope here is 
. Therefore, by plotting these two straight lines, we have that the solution is the origin, that is, the point 
.
The answer is 310.93, rounded to the nearest hundredth. Hope this helps!
Answer:
A
Step-by-step explanation:
Since we're dealing with perpendicular lines, we take the recipricol of the m value of the original equation.
So the slope we're dealing with is 1/2.
And the equation we have so far is
y = 1/2x + b
Now we solve for b by plugging in the point (4,2).
2 = 1/2(4) + b
2 = 2 + b
b = 0
So the final equation is
y = 1/2x
Answer:
1. 21x⁴+3y-35x² + 41
2. -21x⁴-3y+6x² + x
Step-by-step explanation:
When adding and subtracting polynomials , you can use the distributive property to add or subtract the coefficients of like terms.
1. The polynomial is 21x⁴ + 3y -6x² + 34
To obtain polynomial 29x² -7 , we must subtract some polynomial from it.
Let that polynomial be k.
So, 21x⁴ + 3y -6x² + 34 - k = 29x² -7
k = 21x⁴ + 3y - 6x² +34 - 29x² +7 = 21x⁴ + 3y - 35x² + 41
2. To obtain a first degree polynomial, let that polynomial be x +34
So, 21x⁴ + 3y - 6x² + 34 + K = x + 34
K = x + 34 - 21x⁴ -3y + 6x² - 34
= -21x⁴ - 3y + 6x² + x
2 to the power of 6 or 4 to the power of 3
