Answer:
Step-by-step explanation:
1. Answer below
![2x = \sqrt[3]{125}](https://tex.z-dn.net/?f=2x%20%3D%20%5Csqrt%5B3%5D%7B125%7D)
2. Answer below
![x + 3^{2} = \sqrt[3]{27}](https://tex.z-dn.net/?f=x%20%2B%203%5E%7B2%7D%20%3D%20%5Csqrt%5B3%5D%7B27%7D)
we are given that ,
The combined area of two squares is 17 square meters.
Area of square=
Let the side length of smaller square be x
The size of the larger Square are four times as long as the size of the smaller square
So Area of larger square=
The combined Area is 17 square meter.
Hence the smaller square has the side length=
So the larger square has side length=
The question would be:
Which is the best measure of center for first period and why?
Mean, because there are no outliers that affect the center
Median, because there is 1 outlier that affects the center
Interquartile range, because there is 1 outlier that affects the center
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I think the answer would be the fourth choice "</span><span>Standard deviation, because there are no outliers that affect the center"
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I hope my answer has come to your help. God bless and have a nice day ahead!
If you mean average, then it's quite simple.
Usually when you want to find the average of something, you add them up all together and divide by how many there are.
For example, the numbers:
12, 69, 35, 67, and 2.
Steps:
1.) Add them. 12 + 69 + 35 + 67 + 2 = 185
2.) 185 divided by 5.
3.) Answer: 37
3y - x = 6 (Note: the formula for slope-intercept form is y = mx + b)
3y = x + 6 (moving the x over to separate both variables)
y = x/3 + 6/3 (after dividing both sides by 3)
y = x/3 + 2 (simplify)
Hope this helps! :)
