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Marianna [84]
3 years ago
8

−10sin(x)=−4csc(x)+3

Mathematics
1 answer:
tatiyna3 years ago
7 0

-10 sin(x) = -4 csc(x) + 3

Recall that csc(x) = 1/sin(x) :

-10 sin(x) = -4/sin(x) + 3

Multiply both sides by sin(x) :

-10 sin²(x) = -4 + 3 sin(x)

Move everything to one side:

10 sin²(x) + 3 sin(x) - 4 = 0

Factorize the left side:

(2 sin(x) - 1) (5 sin(x) + 4) = 0

Then we have two cases,

2 sin(x) - 1 = 0   or   5 sin(x) + 4 = 0

Solve for sin(x) :

sin(x) = 1/2   or   sin(x) = -4/5

Solve for x :

• if sin(x) = 1/2, then

x = arcsin(1/2) + 2nπ   or   x = π - arcsin(1/2) + 2nπ

x = π/6 + 2nπ   or   x = 5π/6 + 2nπ

• if sin(x) = -4/5, then

x = arcsin(-4/5) + 2nπ   or   x = π - arcsin(-4/5) + 2nπ

x = -arcsin(4/5) + 2nπ   or   x = π + arcsin(4/5) + 2nπ

(where n is any integer)

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!!!!!!!HELP ASAP!!!!!!!!!
Scrat [10]
7/28 = 4/?
4*28 = 112. (a) = 16
112 ÷ 7 = 16.

7/588 = 4/?
4*588 =2,352. (b) = 336
2,352 ÷ 7 = 336

7/686 = 4/?
4*686 = 2,744. (c) = 392
2,744 ÷ 7 = 392
4 0
3 years ago
What is -4k - 7 + 5k ? I need to know the steps in order to do this
MArishka [77]
-4K-7+5k
First. You have to plus the negative 4K in the 5K together which makes it K or
1K
So now you equation would be: k-7
5 0
4 years ago
Read 2 more answers
5. Last year, Mr. Petersen's rectangular garden had a width of 5 meters and an area of 20 square meters.
11111nata11111 [884]

Answer:

Last Year Length = 4 meters

This Year Length = 12 meters

This Year Width = 10 meters

Step-by-step explanation:

We know, area of the rectangle is given by the formula:

Area = Length * Width

Given width = 5

Area = 20

We solve for Length:

Area = Length * Width

20 = Length * 5

Length = 20/5 = 4

Last Year Length = 4 meters

Now, this year, the length would be 3 times as long, so new length would be:

This Year Length = 4 * 3 = 12 meters

This year, the width would be two times previous year, so width would be:

This Year Width = 5 * 2 = 10 meters

5 0
3 years ago
PLEASE HELP ASAP NOO LINKS!!!
storchak [24]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
How do you factorise this using DOPS/DOTS?<br><br> 2(x + 3)^2-10
Margaret [11]

Answer:

Step-by-step explanation:

Hello,

2(x+3)^2-10\\=2[(x+3)^2-5]\\=2[(x+3)^2-(\sqrt{5})^2]\\\\=2[(x+3+\sqrt{5})(x+3-\sqrt{5})]

Hope this helps

4 0
3 years ago
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