Question

If h(x)=9+x², solve for x when h(x)=13

Answer 1

Answer:

I hope you got it. I have presented it clearly and stepwise.

Answer 2

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \bold{ \sf{x = 2}}}}}}$

Step-by-step explanation:

Given, h(x) = 13

To find : value of x

$\sf{h(x) = 9 + {x}^{2} }$

$\longrightarrow{ \sf{13 = 9 + {x}^{2} }}$

Swap the sides of equation

$\longrightarrow{ \sf{9 + {x}^{2} = 13}}$

Move 9 to right hand side and change it's sign

$\longrightarrow{ \sf{ {x}^{2} = 13 - 9}}$

Subtract 9 from 13

$\longrightarrow{ \sf{ {x}^{2} = 4}}$

$\longrightarrow{ \sf{ \sqrt{ {x}^{2} } = \sqrt{4} }}$

$\longrightarrow{ \sf{x = \: \sqrt{ {2}^{{2}} }}}$

$\longrightarrow{ \sf{x = 2}}$

Hope I helped!

Best regards!