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Umnica [9.8K]
3 years ago
15

What is (-m)^-3n if m=2 and n=-24

Mathematics
1 answer:
m_a_m_a [10]3 years ago
4 0
((-m)^-3)*n


first we substitute in both "m" and "n" with their respective values.


((-(2)^-3))*(-24)


then use pemdas (order of operations) to solve


-(2^-3)*-24

-(1/(2^3)*-24

-(1/8)*-24

(1/8)*24

24/8=3


3 is the answer
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Solve the system of equations 5x-2y=88 3x+4y=58 show all work
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The given equations are:

5x - 2y = 88
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Multiplying the 1st equation by 2, we get the new set of equations as:

10x - 4y = 176
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Adding the two equations, we get:

10x - 4y + 3x + 4y = 176 + 58
13x =234
x =  18

Using the value of x in 1st equation, we get:

5(18) - 2y = 88
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-2y = -2
y = 1

So, the solution of the equation is (18, 1)

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= 3x +15 <br> = 4x-10<br><br> What is the value of x?
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Answer:

3x+15= 4x-10

3x-4x= -10-15

-x= -25(minus will be cut on both sides)

so x= 25

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3 years ago
Is anybody better at this then I am ?
lbvjy [14]

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hmmm

Step-by-step explanation:

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3 years ago
Which of these relations on {0, 1, 2, 3} are equivalence relations? Determine the properties of an equivalence re- lation that t
slava [35]

Answer:

The relations that are equivalence relations are a) and c)

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A relation on a set A is called an equivalence relation if it is reflexive, symmetric, and transitive

We are going to analyze each one.

a){ (0,0), (1,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

b){ (0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3) }

Is not an equivalence relation. Not reflexive: (1,1) is missing, not transitive: (0,2) and (2,3) are in the relation, but not (0,3)

c){ (0,0), (1,1), (1,2), (2,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

d){ (0,0), (1,1), (1,3), (2,2), (2,3), (3,1), (3,2) (3,3) }

Is not an equivalence relation. Not transitive: (1,3) and (3,2) are in the relation, but not (1,2)

e){ (0,0), (0,1) (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3) }

Is not an equivalence relation. Not symmetric: (1,2) is present, but not (2,1)Not transitive: (2,0) and (0,1) are in the relation, but not (2,1)

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4 years ago
Find X. Round to the nearest tenth if necessary.
storchak [24]

Answer:

3.2

Step-by-step explanation:

If there are 2 secont lines intersecting inside a circle like the picture shown, then the theorem tells us that <em>"the product of 2 segments of one secant line is equal to the product of 2 segments of other secant line"</em>

<em></em>

Thus, we can say that:

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x = 32/10

x = 3.2

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3 years ago
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