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bezimeni [28]
2 years ago
5

PLEASE HELP ! Find the answer for me pls..

Mathematics
2 answers:
mylen [45]2 years ago
5 0

Answer:

0.6 i belive im not sure tbh look at description

Step-by-step explanation:

Simplifying

2x + 3forx = 3

Reorder the terms:

3forx + 2x = 3

Solving

3forx + 2x = 3

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-2x' to each side of the equation.

3forx + 2x + -2x = 3 + -2x

Combine like terms: 2x + -2x = 0

3forx + 0 = 3 + -2x

3forx = 3 + -2x

Divide each side by '3orx'.

f = o-1r-1x-1 + -0.6666666667o-1r-1

Simplifying

f = o-1r-1x-1 + -0.6666666667o-1r-1

Reorder the terms:

f = -0.6666666667o-1r-1 + o-1r-1x-1

Fofino [41]2 years ago
4 0
The answer is 9
Replace the x with the number given
Since the x is next to the 2 it meant to multiply
2(3)+3=9
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The answer is 

-12y

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7 0
3 years ago
Read 2 more answers
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disa [49]

Answer:

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  • Family 2: $1.350

Step-by-step explanation:

We know that the total monthly payment is 3200, so if we call Pa (family A`s payment) and Pb (Family B's payment) the payments:

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So if we replace Pa in the first ecuation:

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borishaifa [10]

Answer:

495 combinations of 4 students can be selected.

Step-by-step explanation:

The order of the students in the sample is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

How many combination of random samples of 4 students can be selected?

4 from a set of 12. So

C_{n,x} = \frac{12!}{4!(8)!} = 495

495 combinations of 4 students can be selected.

8 0
3 years ago
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