My answer -
<span>1. Use symbols (not words) to express quotient
2. Use exponent symbol (^) to denote exponents
3. Just write out question number, question, and choices. No need for
extra information (such as points). Also, don't leave blank lines
between choices. This extraneous that we don't need just makes your
whole question very very long, and means a lot of scrolling on our part.
4. You should only post 2 or 3 questions at a time.
1) (6x^3 − 18x^2 − 12x) / (−6x) = −x^2 + 3x + 2 ----> so much simpler to read !
2) (d^7 g^13) / (d^2 g^7) = d^(7−2) g^(13−7) = d^5 g^6 ----> much easier to read !
3) (4x − 6)^2 = 16x^2 − 24x − 24x + 36 = 16x^2 − 48x + 36
4) (x^2 / y^5)^4 = (x^2)^4 / (y^5)^4 = x^8 / y^20
5) (3x + 5y)(4x − 3y) = 12x^2 − 9xy + 20xy − 15y^2 = 12x^2 + 11xy − 15y^2
6) (3x^3y^4z^4)(2x^3y^4z^2) = (3*2) x^(3+3) y^(4+4) z^(4+2) = 6 x^6 y^8 z^6
7) 5x + 3x^4 − 7x^3 ----> Fourth degree trinomial
8) (5x^3 − 5x − 8) + (2x^3 + 4x + 2) = 7x^3 − x − 6
9) (x − 1) + (2x + 5) − (x + 3) = x + 1
10) (−4g^8h^5k^2)0(hk^2)^2 = 0 (anything multiplied by 0 = 0)
or.. (−4g^8h^5k^2)^0(hk^2)^2 = 1 (h^2 (k^2)^2) = h^2 k^4
Last question shows why it is so important to use proper symbols (such
as ^ to indicate exponents). Without such symbols, I could not tell if
the 0 was an actual number and part of multiplication, of if 0 was an
exponent of the expression preceding it.
P.S
Glad to help you have an AWESOME!!! day :)
</span>
Answer:
10 stops I think as the 0.2 is not a full mile so you dont stop
Step-by-step explanation:
Let the angle be x and it's complement be c.
Then, x = c + 88 and x + c = 90
Substitute the first equation in the second.
(c+88) + c = 90
2c+88 = 90
2c = 2
c =1
Compliment = 1
Angle = 89
You can do
3 * 2 and 11 * 2 which would be 6:22 and is still equal to the ratio 3:11. Your explanation can be the when divided by 2 or the number you multiplied by, you would get the original ratio
Examples:
6:22
9:33
12:44
