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stich3 [128]
3 years ago
13

This Question: 1 pt

Mathematics
1 answer:
horrorfan [7]3 years ago
8 0

Answer: the length of the field is 70 yards. The width of the field is 35 yards

Step-by-step explanation:

Let L represent the length of the rectangular athletic field.

Let W represent the width of the rectangular athletic field.

A rectangular athletic field is twice as long as it is wide. This means that

L = 2W

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

If the perimeter of the athletic field is 210 yards, it means that

210 = 2(L + W)

L + W = 210/2 = 105

Substituting L = 2W into L + W = 105, it becomes

2W + W = 105

3W = 105

W = 105/3 = 35

L = 2W = 2 × 35

L = 70

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Answer:

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A(-3, 0) , B(3, 2)

AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}

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