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OlgaM077 [116]
3 years ago
14

PLEASE HELP ME!! IM STUCK!!

Mathematics
2 answers:
Jlenok [28]3 years ago
6 0
I think it a because it the top is the second one, but I am not sure.
Tomtit [17]3 years ago
3 0
If you look from the left, the left row has one pile 2 cubes high.
The middle row has 3 piles. The tallest one is 3 cubes high.
The right row has 2 piles, both 1 cube high.
The answer is Choice A.
You might be interested in
A linear function h models a relationship in which the dependent variable decreases 2 units for every 3 units the independent va
ratelena [41]

Answer:

Slope=-2/3,  y-intercept=2, x-intercept=3

Step-by-step explanation:

Let the independent variable be x and dependent variable be y

y=h(x)

h is a linear function so it is represented in the general form of y=mx+c where

m is slope and c is the y-intercept.


Given "the dependent variable decreases 2 units for every 3 units the independent variable increases."

When x increases by 3, y decreases by 2

So the slope = rate of change of y / rate of change of x = -2/3


Given h(0)=2, h(0)=m(0)+c=2

c=2


Combining slope and y-intercept, y=-2/3*x+2

x-intercept is when y=0

0=-2/3*x+2

2/3*x=2

x=2*3/2=3

x-intercept=3


6 0
3 years ago
Read 2 more answers
PLEASE HELP ILL MARK YOU BRAINLIEST
mr Goodwill [35]

Answer:

D is the correct a

Step-by-step explanation:

From table A-3: Areas under the normal curve

we can deduce that k=0.9

7 0
2 years ago
Let f(x)=6/5x−1/2. Describe the transformations from the graph of f to the graphs of g(x)=−f(x) and h(x)=f(−x).
aivan3 [116]

Answer:

g(x)=-6/5x+1/2

h(x)=-6/5x-1/2

Step-by-step explanation:

1).   g(x)=−f(x) ?

f(x)=6/5x−1/2

g(x)=−(6/5x−1/2)

<u>g(x)=-6/5x+1/2</u>

2). h(x)=f(−x) ?

f(-x)=6/5(-x)−1/2

f(-x)=-6/5x-1/2

h(x)=-6/5x-1/2

8 0
3 years ago
please do the steps solve the equation for d: 1/6d-8=5/8 2. Solve the equation for x: 3x-4+5x=10-2z 3. Solve the equation for c:
Ulleksa [173]

Step-by-step explanation:

1. 1/6d - 8 = 5/8

1/6d -8 + 8 = 5/8 + 8

1/6d = 69/8

1/6d / 1/6 = 69/8 / 1/6

d = 51.75 or 51\frac{3}{4}

2. 3x - 4 + 5x = 10 - 2z

8x - 4 = 10 - 2z

8x - 4 + 4 = 10 - 2z + 4

8x = 14 - 2z

8x / 8 = (14 - 2z) / 8

x = \frac{14 - 2z}{8}

3. 7(c  - 3) = 14

7(c - 3) / 7 = 14 / 7

c - 3 = 2

c - 3 + 3 = 2 + 3

c = 5

4. 11(m / 22 + 3 / 44) = 87

m / 22 + 3 / 44 = 87 / 11

m / 22 + 3 / 44 = 348 / 44

m / 22 = 345 / 44

m = 172.5

5. ck + 5k = a

k(c + 5) = a

k = \frac{a}{c+5}

8 0
3 years ago
Suppose that production of 1 unit of mining requires 33​/77 unit of​ mining, 22​/77 unit of​ manufacturing, and 22​/77 unit of c
taurus [48]
The ratio should be written as:

mining:manufacturing:communication

Since there are three varieties of ratio's, then there is a specific answer for each. For the first example, the ratio is written as:

33/77:22/77:22/77
To find the integer ratio, divide all numbers with the smallest value, 22/77. The ratio becomes: 1.5:1:1

For the second example,
55/77:11/77:11/77
To find the integer ratio, divide all numbers with the smallest value, 11/77. The ratio becomes: 5:1:1

For the third example,
0:11/77:66/77
For this, exclude the ratio for mining because if you use this as the value, then all the numbers would be zero. Instead, divide using 11/77. The ratio becomes: 6:1.
5 0
3 years ago
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