Answer:
1
Step-by-step explanation:
you asked to type 1
Answer:
x = 3 ±sqrt(6)
Step-by-step explanation:
6(x-3)^2-26 = 10
Add 26 to each side
6(x-3)^2-26+26 = 10+26
6(x-3)^2 = 36
Divide by 6
6/6(x-3)^2 = 36/6
(x-3)^2 = 6
Take the square root of each side
sqrt((x-3)^2) = ±sqrt(6)
x-3 = ±sqrt(6)
Add 3 to each side
x-3+3 =3 ±sqrt(6)
x = 3 ±sqrt(6)
80 because if you multiply all them you would get 64,000 then divide it
Answer: The correct option is (1) Dependent.
Step-by-step explanation: For two events, we are given the following values of the probabilities :
P(A ∩ B) = 0.20, P(A) = 0.49 and P(B) = 0.41.
We are to check whether the events A and B are independent or dependent.
We know that
the two events C and D are said to be independent if the probabilities of their intersection is equal to the product of their probabilities.
That is, P(C ∩ D) = P(C) × P(D).
For the given two events A and B, we have

Therefore, the probabilities of the intersection of two events A and B is NOT equal to the product of the probabilities of the two events.
Thus, the events A and B are NOT independent. They are dependent events.
Option (1) is CORRECT.
Let c represent the number of cars that the salesman has left to sell.
68 + c ≤ 125
68-68 + c ≤ 125 -68
c≤57
The solution is c ≤ 57. The salesman has at most 57 cars left to sell
Answer:
68 + c ≤ 125; c ≤ 57 cars or less left to sell.