Answer:
56 different tests
Step-by-step explanation:
Given:
Number of wires available (n) = 8
Number of wires taken at a time for testing (r) = 5
In order to find the number of different tests required for every possible pairing of five wires, we need to find the combination rather than their permutation as order of wires doesn't disturb the testing.
So, finding the combination of 5 pairs of wires from a total of 8 wires is given as:

Plug in the given values and solve. This gives,

Therefore, 56 different tests are required for every possible pairing of five wires.
Answer:
P(x)= x ^4-3x^3+x^2-4
Step-by-step explanation:
Given data
R(x) = 2x ^4-3x^3+2x-1
c(x)=x^4-x^2+2x+3
We know that
P(x)=R(x)-C(x)
Hence
P(x)= 2x ^4-3x^3+2x-1-(x^4-x^2+2x+3)
open bracket
P(x)= 2x ^4-3x^3+2x-1-x^4+x^2-2x-3
Collect like terms
P(x)= 2x ^4-x^4-3x^3+x^2-2x+2x-3-1
P(x)= x ^4-3x^3+x^2-4
The answer is 3a + 2b + 8
It is the lateral edge as it is an edge and it is on the lateral area.