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3 years ago

What are the important things to remember when describing the setting of a story brainly.

1 answer:

4 0

Use the senses to help the reader feel as if they are there. instead of just describing what can be seen describe the sounds and smells of the setting too so that it gives more vivid imagery.

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Name two ideas that can be marketed

GenaCL600 [577]

Events and experiences maybe?

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4 years ago

Which two factors could increase the carrying capacity of an ecosystem?

Setler [38]

Answer:

the amount of food available, the local extinction of a competitor, an increase in species fertility, a decrease in predation

Explanation:

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3 years ago

The anticoagulant in a gray-stoppered blood collection tube is:

mamaluj [8]

Answer:

potassium oxalate and sodium fluoride

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2 years ago

A point charge q1 = -4. 00 nc is at the point x = 0. 60 m, y = 0. 80 m , and a second point charge q2 = +6. 00 nc is at the poin

Alekssandra [29.7K]

The net electric field is the vector sum of the components of the electric

field produced by the two charges.

The values of the magnitude and direction of the net electric field at the origin (approximate values) are;

131.6 N/C

12.6 ° above the negative x–axis

<h3>How are the net electric field magnitude and direction calculated?</h3>

The possible questions based on a similar question posted online are;

(a) The net electric field at the origin.

The electric field due to charge q₁ is given as follows;

$\vec E_{1x} = \mathbf{ \dfrac{1}{4 \cdot \pi \cdot \epsilon_0} \cdot \dfrac{q_1}{\vec{r}^2_2}}$

Which gives;

$\vec{E}_{1x} =\mathbf{ \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot cos\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) =-21.6 \, N/C$

$\vec{E}_{1y} = \mathbf{\dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot sin\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) = 28.8 \, N/C$

Which gives;

$\vec{E}_1 = \mathbf{21.6 \, N/C \cdot \hat x + 28.8 \, N/C \hat y}$

$\vec{E}_{2x} = \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(6.00 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2} = 150 \, N/C$

Therefore;

$\vec {E} = \left[ 21.6 \, N/C - 150 \, N/C \right] \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)$

$\vec {E} = \mathbf{\left( -128.4 \, N/C \right) \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)}$

The magnitude of the net electric field is therefore;

E = $\sqrt{(-128.4^2 + 28.8^2)}$ ≈ 131.6

The magnitude of the net electric field at the origin is E ≈<u> 131.6 N/C</u>

(b) The direction of the net electric field at the origin.

$The \ direction \ is \ arctan \left(\dfrac{28.8}{-128.4} \right) \approx \underline{ 12.6^{\circ}} \ above \ the \ negative \ x-axis$

Learn more about electric field strength here:

brainly.com/question/14743939

brainly.com/question/3591946

3 0

2 years ago

Among fatal plane crashes that occurred during the past 65 years, 374 were due to pilot error, 51 were due to other human error,

notka56 [123]

Mechanical problems since they can be solved and have the second most deaths. I would have the plane go through at least 3 examinations before boarding then one passenger exam before takeoff.

7 0

4 years ago