Are s^2 ,2s^2 and 3s^2 equivalent
1 answer:
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9514 1404 393
Answer:
see below
Step-by-step explanation:
Starting from the point-slope equation ...
y -y1 = m(x -x1)
Solving for y gives ...
y = mx +(y1 -m·x1)
So, the slope-intercept form equation is fairly easily found:
y = mx +b . . . . where m = m, and b = y1-m·x1
This is the equation we have used for 'b' in the attached spreadsheet.
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Of course, the formula for slope is ...
m = (y2 -y1)/(x2 -x1)
This is the equation we have used for 'm' in the attached spreadsheet. For all problems, we have used the first point. (It doesn't matter which point you use if there are two of them.)
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The second attachment is the Google Sheets spreadsheet saved in ODS format. Most spreadsheet programs should be able to open that so you can see the formulas, if you're interested. (The gray values of m are computed using the two points. The unshaded values of m are entered by hand.)
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I'll write a couple of equations in each group so you can see how the spreadsheet numbers relate:
y = mx +b
1. y = 2x -7
3. y = 2/3x +4
8. y = 1/3x -5
9. y = -5/2x +4
Answer:
The volume of the regular tetrahedron is 283.5 m³
Step-by-step explanation:
The formula of the volume of the regular tetrahedron is V = A h, where
- A is the base area of it
- h is the height of it
∵ The area of the base of a regular tetrahedron is 98.9 m²
∴ A = 98.9 m²
∵ The height of it is 8.6 m
∴ h = 8.6 m
→ Substitute them in the formula of the volume above
∵ V = (98.9)(8.6)
∴ V = 283.5133333 m³
→ Round it to the nearest tenth of a cubic meters
∴ V = 283.5 m³
∴ The volume of the regular tetrahedron is 283.5 m³