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2 years ago

Please help me give brainliest

Mathematics

1 answer:

Cloud [144]2 years ago

3 0

Answer:

d and b

Step-by-step explanation:

the minimums and maximums of each make the most sense so it'd be d for the first and b for the second

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Mrs ray is teaching a 5th grade class . She is standing 5 meters in front of Kiara. Ian is sitting 12 meters directly to Kiara’a

Kaylis [27]

The answer is going to be b

8 0

2 years ago

Given f(x)=4x+5 and g(x)= x^2+x; find (f∘g)(-5) Please show all steps thank you

Greeley [361]

Answer:

$(f\circ g)(-5)=85$

Step-by-step explanation:

We are given:

$\displaystyle f(x)=4x+5\text{ and } g(x)=x^2+x$

And we want to find:

$(f\circ g)(-5)$

This is equivalent to:

$\displaystyle =f(g(-5))$

So, we will evaluate g(-5) first, which yields:

$\displaystyle g(-5)=(-5)^2+(-5)=25-5=20$

So:

$=f(g(-5))=f(20)$

Then:

$\displaystyle f(20)=4(20)+5=80+5=85$

Therefore:

$(f\circ g)(-5)=85$

6 0

3 years ago

4. A bag contains five red marbles, two orange marbles, one yellow marble, and two green marbles. Two marbles are drawn from the

Vitek1552 [10]

Answer:

C. 0.08889

Step-by-step explanation:

Total number of marbles:

5 + 2 + 1 + 2 = 10

There are two possibilities

Orange then green or green the orange

The probabilities are:

P(o&g) = 2/10*2/9 = 2/45
P(g&o) =2/10*2/9 = 2/45

Required probability is:

P = 2/45*2 = 4/45 = 0.08889

Correct choice is C

4 0

2 years ago

Which of the following indicates that the roots of a quadratic are irrational

yan [13]

Answer would be D You can have a rational discriminant for an irrational root, but you can also have rational discriminant for a rational root. So C is partially correct.

All prime discriminants will result in an irrational root, but not all irrational roots have prime discriminants

6 0

3 years ago

Solve for x x^2-2x+1=0

Molodets [167]

Answer:

x=1

Step-by-step explanation:

By factoring, you'll compress the equation to (x-1)^2=0

Next take out the square: x-1=0

Now subtract one to the other side to get x! x=1

Hope this helps! :)

3 0

3 years ago