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2 years ago

PLEASE I WILL GIVE YOU BRAINLIEST JUST HELP ME I LOVE YOUUUUUUUU

Mathematics

1 answer:

Ivenika [448]2 years ago

5 0

Answer:

x=30

Step-by-step explanation:

90+130+x+10+x+x+x=360

230+3x=360

3x=90

x=30

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Plz help me do this branniest to whoever right

Phantasy [73]

Answer:

<1 = 114° and <2 = 66°

Step-by-step explanation:

The two angles measure 66 degrees and 114 degrees because the sum of supplementary angles is 180 degrees.

Explanation:

Supplementary angles are two angles with a sum of 180 degrees.

Let the smaller angle = x

If the two angles differ by 48 degrees, the bigger angle is 48 degrees more and equals

x+48

The sum of the two angles is 180, so...

x+x+48=180

Add the variableterms

2x+48=180

Subtract 48 from both sides

2x=132

Divide both sides by 2

2x/2=132/2

x=66

This is the measure of the smaller angle.

The bigger angle = x+48=114

5 0

2 years ago

Help? (1# only) In really confused :(

insens350 [35]

I’m is to it’s a lot of numbers 3467632

7 0

2 years ago

3x-y=-5 5x+7y=29 Solve this for me using substitution pls

pentagon [3]

Answer:

(- 3/13, 56/13)

Step-by-step explanation:

See steps below:)

3 0

2 years ago

F=(2xy +z³)i + x³j + 3xz²k find a scalar potential and work done in moving an object in the field from (1,-2,1) to (3,1,4)

Alex73 [517]

Step-by-step explanation:

Given:

$\textbf{F} = (2xy + z^3)\hat{\textbf{i}} + x^3\hat{\textbf{j}} + 3xz^2\hat{\textbf{k}}$

This field will have a scalar potential $\varphi$ if it satisfies the condition $\nabla \times \textbf{F}=0$ . While the first x- and y- components of $\nabla \times \textbf{F}$ are satisfied, the z-component doesn't.

$(\nabla \times \textbf{F})_z = \left(\dfrac{\partial F_y}{\partial x} - \dfrac{\partial F_x}{\partial y} \right)$

$\:\:\:\:\:\:\:\:\: = 3x^2 - 2x \ne 0$

Therefore the field is nonconservative so it has no scalar potential. We can still calculate the work done by defining the position vector $\vec{\textbf{r}}$ as

$\vec{\textbf{r}} = x \hat{\textbf{i}} + y \hat{\textbf{j}} + z \hat{\textbf{k}}$

and its differential is

$\textbf{d} \vec{\textbf{r}} = dx \hat{\textbf{i}} + dy \hat{\textbf{j}} + dz \hat{\textbf{k}}$

The work done then is given by

$\displaystyle \oint_c \vec{\textbf{F}} • \textbf{d} \vec{\textbf{r}} = \int ((2xy + z^3)\hat{\textbf{i}} + x^3\hat{\textbf{j}} + 3xz^2\hat{\textbf{k}}) • (dx \hat{\textbf{i}} + dy \hat{\textbf{j}} + dz \hat{\textbf{k}})$

$\displaystyle = (x^2y + xz^3) + x^3y + xz^3|_{(1, -2, 1)}^{(3, 1, 4)}$

$= 422$

5 0

3 years ago

Can someone helppp me

stiks02 [169]

Step-by-step explanation:

To find the Circumference of a triangle you use the formula C= 2(pi)r

in both of the problems you have the radius(r) and you plug the #'s in and solve

(pi)= 3.14...

#1.

2(pi)14.5

28(pi)

C= 87.92

#2.

2(pi)9.5

19(pi)

C= 56.66

6 0

2 years ago