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Rufina [12.5K]
2 years ago
9

the atomic number and atomic weight of chlorine element is 17 and 35 respectively. Calculate the number of proton, neutron and e

lectron​
Mathematics
2 answers:
laila [671]2 years ago
6 0
  • No of protons=Atomic No=17
  • No of electrons=No of protons=17
  • No of neutrons=Massno-No of protons

\\ \sf\longmapsto 35-17

\\ \sf\longmapsto 18neutrons

Xelga [282]2 years ago
6 0

Answer:

protons = 17 \\ electrons = 17 \\ neutrons = 18

Step-by-step explanation:

*The number of protons = The atomic number

So,

17 = 17

*The number of protons = The number of electrons

So,

17 = 17

*The number of neurons = (Mass number - The number of protons)

18 = 35 - 17

Hope this helps you

Let me know if you another questions :-)

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The common difference is the number that we are adding or subtracting to reach the next term in the sequence.

Notice that the difference between 15 and 12 is 3.

In other words, 12 + 3 = 15.

That 3 that we are adding is our common difference.

So we know that our first term is 12.

Now we can continue the sequence.

12 ⇒ <em>1st term</em>

15 ⇒ <em>2nd term</em>

18 ⇒ <em>3rd term</em>

21 ⇒ <em>4th term</em>

24 ⇒ <em>5th term</em>

27 ⇒ <em>6th term</em>

30 ⇒ <em>7th term</em>

33 ⇒ <em>8th term</em>

36 ⇒ <em>9th term</em>

39 ⇒ <em>10th term</em>

42 ⇒ <em>11th term</em>

45 ⇒ <em>12th term</em>

48 ⇒ <em>13th term</em>

51 ⇒ <em>14th term</em>

54 ⇒ <em>15th term</em>

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60 ⇒ <em>17th term</em>

63 ⇒ <em>18th term</em>

66 ⇒ <em>19th term</em>

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This means that the 20th term of this arithemtic sequence is 69.

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Step-by-step explanation:

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3 years ago
How can i differentiate this equation?
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\bf y=\cfrac{2x^2-10x}{\sqrt{x}}\implies y=\cfrac{2x^2-10x}{x^{\frac{1}{2}}} \\\\\\ \cfrac{dy}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2}x^{-\frac{1}{2}} \right)}{\left( x^{\frac{1}{2}} \right)^2}} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2\sqrt{x}} \right)}{\left( x^{\frac{1}{2}} \right)^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x}


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3 years ago
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