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eimsori [14]
3 years ago
13

Can someone help and I need it quick

Mathematics
1 answer:
kvasek [131]3 years ago
8 0

Answer:

The change in momentum between 0 ms and 14 ms is 0 kg•m/s

Step-by-step explanation:

Here, we want to calculate the change in momentum using the graphical illustration

This is same as the slope using the two points

Let us have 2 expressions of (x,y)

Mathematically, that will be obtained from the graph as follows;

At 0 ms, we have 0 N

At 14 ms , we also have 0

So the two points we are considering are;

(0,0) and (14,0)

= (0-0)/(14-0) = 0/14 = 0 N/ms

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Answer:it’s 3 and 8

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Area = 634.21 square metre

Step-by-step explanation:

Area of shaded region = Area of the circle - Area of the sector

Area \ of \ the \ circle = \pi r^2 = 225 \pi\\\\Area \ of \ the \ sector = \pi r^2 \frac{ \theta}{360} = \pi \times 225 \times \frac{37}{360}

Area \ of \ shaded \ region = 225 \pi - (225 \pi \times  \frac{37}{360})

                                   = 225 \pi (1 - \frac{37}{360})\\\\= 225 \pi \times 0.89722\\\\=634.21 m^2

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14-6 over 3--2
8/5

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A researcher compares differences in positivity between participants in a low-, middle-, or upper-middle-class family. If she ob
777dan777 [17]

Answer:

(2, 12)

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

If we assume that we have 3 groups and on each group from j=1,\dots,n_j we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2  

SS_{between=Treatment}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2  

And we have this property  

SST=SS_{between}+SS_{within}  

The degrees of freedom for the numerator on this case is given by df_{num}=k-1=3-1=2 where k =3 represent the number of groups.  

The degrees of freedom for the denominator on this case is given by df_{den}=df_{between}=N-K=15-3=12.  

And the total degrees of freedom would be df=N-1=15 -1 =14  

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(2, 12)

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