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n200080 [17]
3 years ago
7

Given that ABCD is a rhombus, what is the value of x?​

Mathematics
2 answers:
Alchen [17]3 years ago
5 0

Hi! Can you post a picture of the rhombus plz? Thx!

Zielflug [23.3K]3 years ago
3 0
Option b, 38 hope that this helps
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Explanation:

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An angle is drawn in standard position passing through the unit circle at (0.643,0.766). The angle in standard position θ has a
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<h2>Hello!</h2>

The asnwer is: Cos50° ≈ 0.643

<h2>Why?</h2>

A unit circle is a cirgle with a radius equal of 1, knowing that,  also know the following:

The angle is drawn passing trough the unit circle at (0.643,0.766) it means that:

x=0.643\\y=0.766

So,

Cos50° ≈ 0.643

We can prove that by following the next steps:

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1^{2}=0.643^{2}+0.766^{2}

1^{2}=0.4134 +0.5867

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- We can determine the cosine of the angle by the following formula:

cos(\alpha)=\frac{x}{hypotenuse} \\cos(\alpha)^{-1}=cos(\frac{0.643}{1})^{-1} \\\alpha=49.98

Therefore,

Cos(α)=49.98°≈50°

Also, if there is a right triangle, according to the Pythagorean Thorem:

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Hence,

Cos50° ≈ 0.643

Have a nice day!

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We can tell it’s not a permutation because it’s picking two people. Order doesn’t matter.

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