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Alchen [17]
3 years ago
14

Dave runs a 10km race and beats his best time by 5%.

Mathematics
1 answer:
jekas [21]3 years ago
7 0

Answer:

57 minutes

Step-by-step explanation:

Simply what is %5 of 60.

%5 of 60 can be found by multiplication by 0.05 x 60 giving you 3.

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Jenny works in a picture framing shop. She has a function f(x) equals X +2 that find the size of a square frame, given a picture
Iteru [2.4K]

Given:

The function for size of a square frame is

f(x)=x+2

where, x is the side length of the picture.

The function for the price in dollars for the frame is

p(x)=3x

To find:

The single function for the price of a picture with an edge length of x.

Solution:

We know that, for a picture with an edge length of x.

Size of a square frame = f(x)

Price in dollars for the frame = p(x)

Single function for the price of a picture with an edge length of x is

(p\circ f)(x)=p(f(x))

(p\circ f)(x)=p(x+2)       [\because f(x)=x+2]

(p\circ f)(x)=3(x+2)           [\because p(x)=3x]

Let the name of this function is c(x). So,

c(x)=3(x+2)

Therefore, the required function is c(x)=3(x+2).

8 0
3 years ago
PLEASE HELP ASAP !!!!! What would these be in scientific notation ?
Zarrin [17]

\text{the scientific notation}\\\\a\cdot10^n\ \text{where}\ 1\leq a < 10\ \text{and}\ n\in\mathbb{Z}

5\underbrace{7,909,000}_{\leftarrow7}km=5.7909\cdot10^7km\\\\1\underbrace{08,200,000}_{\leftarrow8}km=1.082\cdot10^8km\\\\1\underbrace{49,600,000}_{\leftarrow8}km=1.496\cdot10^8km\\\\2\underbrace{27,940,000}_{\leftarrow8}km=2.2794\cdot10^8km\\7\underbrace{78,330,000}_{\leftarrow8}km=7.7833\cdot10^8km\\\\1,\underbrace{424,600,000}_{\leftarrow9}km=1.4246\cdot10^9km\\\\4,\underbrace{498,252,900}_{\leftarrow9}km=4.4982529\cdot10^9km

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3 years ago
Lauren's science class is taking a field trip to the nearest natural history museum. The
Orlov [11]

Answer:60

Step-by-step explanation:

0

5 0
3 years ago
What is the sum of 4.34
nirvana33 [79]
What is the rest of the expression?
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3 years ago
1. 800 divided by 4
grigory [225]
I did the work for you. I also showed my work. Hope it helped

4 0
4 years ago
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