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fenix001 [56]
2 years ago
11

The diagrams show a right angled triangle and a rectangle.

Mathematics
2 answers:
Mrrafil [7]2 years ago
8 0

Answer:

hope it helps you......................

melamori03 [73]2 years ago
6 0

Answer:

x = 5

Step-by-step explanation:

The area (A) of the triangle is calculated as

A = \frac{1}{2} bh ( b is the base and h the height )

Here b = 8 and h = 15 , then

A = \frac{1}{2} × 8 × 15 = 4 × 15 = 60 cm²

The area of the rectangle is also 60 cm² , then

length × breadth = 60 , that is

12x = 60 ( divide both sides by 12 )

x = 5

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keeping in mind the role the order of precedence plays in equations, what would excel display as the result of the following equ
Alex73 [517]
The answer to youre question is 5.5
8 0
3 years ago
Quadrilateral ABCD is a square. if m
olganol [36]
The answer is B. 18

Explanation:

We know that a square has 4 right angles. A right angle is 90°.

5x° = 90°
5(18)° =90°
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Hope this helps some
4 0
3 years ago
Theo drove 236 miles in 4 hours. Lex drove 195 miles in 3 hours. At those rates, could either man drive 116 miles in 2 hours? Sh
motikmotik

Answer:

No.

Step-by-step explanation:

236÷4=59

     &

195÷3=65

<em>To check if either of them drove 116 miles in 2 hours, I would multiply the sum of the division problems by 2(for 2 hours).</em>

59 x 2 = 118

      &

65 x 2 = 130

None of them equals 116, meaning neither of them drove 116 miles in 2 hours.

<u><em>Hope I helped you! Have a great day! :)</em></u>

6 0
3 years ago
Please help as soon as possibly with this math question will give brainlyest
vovikov84 [41]
This is the answer for ur question

5 0
3 years ago
(10.02)
melisa1 [442]

Answer:

sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}

Therefore:

sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}

cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}

Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}

4 0
3 years ago
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